<h3>
<u>Answer:</u></h3>
52.38 inch² & 261.90 inch²
<h3>
<u>Step-by-step explanation:</u></h3>
Here we need to find the area of the sector . So according to formula we know the area of sector as ,
Here we can see that the central angle subtended by the arc is 60° and the radius of the circle is 10 inches . So the required area would be ,
=> Area = ∅/ 360° × π r²
=> Area = 60°/360° × 22/7 × (10in.)²
=> Area = 1/6 * 22/7 * 100 in²
=> Area = 52 .380 in²
<h3>
<u>★</u><u> </u><u>Hence </u><u>the </u><u>area </u><u>o</u><u>f </u><u>the </u><u>red</u><u> </u><u>sector </u><u>is </u><u>5</u><u>2</u><u>.</u><u>3</u><u>8</u><u> </u><u>inch²</u><u>.</u></h3>
<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>
Now let's find out the area of blue sector .The angle subtended by the arc will be (360-60)°=300° .
=> Area = 300/360 × 22/7 × 100 in²
=> Area = 261. 90 in²
<h3>
<u>★</u><u> </u><u>H</u><u>ence </u><u>the </u><u>area </u><u>of </u><u>blue </u><u>sector </u><u>is </u><u>2</u><u>6</u><u>1</u><u>.</u><u>9</u><u>0</u><u> </u><u>inch</u><u>²</u><u>.</u></h3>


We are given with a circle and we need to find the <em>equation of the circle</em> , but first let's recall that , the equation of a circle with radius<em> 'r'</em> and centre at <em>(h,k) </em>is given by
Now , here as as the circle cuts the +ve x-axis at (9,0) . So , it's radius is 9 units or the 2nd way is to measure the distance from centre of the circle to the point where the circle cuts the graph , as the centre is at Origin , so here <em>(h,k) = (0,0)</em> .Which means that the centre is located at the point whose coordinates are<em> (0,0)</em> which is also known as origin . Now , finding the equation of the circle :-


<em>This is the required equation of Circle</em>
Answer:
Line R, S, and P are parallel lines meaning any lines that pass through them will form the same angles. Look at 4 and 2. One line is intersecting S and P to for the same angles. Corresponding angles in parallel lines which are formed by an intersecting line are equal. Therefore 4 and 2 are equal. That leaves B, C, and D left. 4 is also congruent to 5. This is because if 4 is congruent to 2 and 2 is congruent to 5 by vertical angles theorem, 5 must be equal to 4 (transitive property of equality: is a=b and b=c then a=c)
That leaves B and D left. Notice the angle made at the very top left. Across from that unlabeled angle is 6. By vertical angles theorem those 2 angles are congruent. The unmarked angle is equal to 2 and 4 because corresponding angles in parallels are congruent. Therefore lets mark that unmarked angle as 0. If the m< 6 = m< 0 and the m<0= the m<4 then m<6 must equal the m<4.
That leaves Just B remaining thus B is NOT congruent to 4
<3 is the answer
Step-by-step explanation:
"For a rhombus the diagonals are congruent" is the statement among the following choices given in the question that is not always true. The correct option among all the options that are given in the question is the third option or the penultimate option or option "C". I hope the answer has come to your help.
Answer:
25
Step-by-step explanation:
15+0.25m-15 =20+0.05m -15 subtracted 15 from both sides
0.25m-0.05m=5+0.05m -0.05m(I got 5 because i simplified 20-15=5) Subtracte 0.05m from both sides
.2m/.2=5/.2 divde by .2 on both sides to get m by itself
<h2><u><em>
m=25</em></u></h2>