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3 years ago

Why are outer electrons of some substances able to be removed by friction?

Chemistry

2 answers:

svlad2 [7]3 years ago

8 0

<span>The outer electrons are not as tightly bound as ones closer to the nucleus</span>

MrRa [10]3 years ago

6 0

Explanation:

It is known that nucleus of an atom contains protons and neutrons. Protons have a positive charge whereas neutrons have no charge.

Therefore, electrons closer to the nucleus are strongly held due to the force of attraction between opposite charges of protons and electrons.

So, as the electrons go far away from the nucleus then force of attraction between the nucleus and electrons decreases.

As a result, it becomes easier to remove valence electrons of an atom. Thus, they can be removed by friction.

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The exhaust gas from an automobile contains 1.5 percent by volume of carbon monoxide. What is the concentration of CO in mg/m' a

FrozenT [24]

Answer:

(a) 17,178 mg/m3

(b) 11,625 mg/m3

Explanation:

The concentration of CO in mg/m3 can be calculated as

$C (mg/m3) =(P/RT)*MW*C_{ppm}$

For standard conditions (1 atm and 25°C), P/RT is 0.0409.

Concentration of 1.5% percent by volume of CO is equivalent to 1.5*10,000 ppm= 15,000 ppm CO.

The molecular weigth of CO is 28 g/mol.

(1) For 25°C and 1 atm conditions

$C=(P/RT)*MW*C_{ppm}\\\\C=0.0409*28*15,000=17,178$

(b) For 200°C and 1.1 atm,

$P/RT=0.0409*(P/P_{std})*(T_{std}/T)\\P/RT=0.0409*(1.1atm/1atm)*(273+15K/273+200K)=0.0277$

Then the concentration in mg/m3 is

$C=(P/RT)*MW*C_{ppm}\\\\C=0.0277*28*15,000=11,625$

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