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Licemer1 [7]
3 years ago
5

What is the mole ratio of c4h10 to co2 in the reaction 2C4H10+13O2->8CO2+10H2O??

Chemistry
1 answer:
pychu [463]3 years ago
4 0

Answer:

  • <em>The mole ratio of C₄H₁₀ and CO₂ is</em><u> 2 : 8, which  simplifies to 1 : 4</u>.

Explanation:

The<em> mole ratio</em> is the relative proportion of the moles of products or reactants that participate in the reaction according to the chemical equation.

The chemical equation given is:

  • 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O

Once you check that the equation is balanced, you can set the <em>mole ratios</em> for all the reactants and products. The coefficients used in front of each reactant and product, in the balanced chemical equation, tells the mole ratios.

In this case, they are: 2 mol C₄H₁₀ :  13 mol O₂ : 8 mol CO₂ : 10 mol H₂O

Since you are asked about the mole ratio of C₄H₁₀ and CO₂ it is:

  • 2 mol C₄H₁₀ : 8 mol CO₂ , which dividing by 2, simplifies to
  • 1 mol C₄H₁₀ : 4 mol CO₂, or
  • 1 : 2.
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The reaction that has the greatest tendency to be reversed in an spontaneous redox reaction is that whose forward standard reduction potential is the lowest (mos negative) one because that means that the reversed reaction will have the highest (most positive) standard reduction potential.

So, the answer is Cr(3+) + 3e-    ---> Cr(s) with Eo = -0.91 V, whose reversed reaction is Cr(s) - 3e-         ---> Cr (3+) with Eo = +0.91 V.

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When 74.8g of alanine C3H7NO2 are dissolved in 1450.g of a certain mystery liquid X, the freezing point of the solution is 8.30°
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Answer: The mass of potassium bromide that must be dissolved in the same mass of X to produce the same depression in freezing point is 58.2 grams

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Depression in freezing point is given by:

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\Delta T_f=T_f^0-T_f=8.30^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

K_f = freezing point constant =  

m= molality = \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}=\frac{74.8g\times 1000}{1450g\times 89.09g/mol}=0.579

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Given what we know about ratios, we can confirm that in comparison to the iron pan, the aluminum pan will receive twice as much heat.

<h3>Why would the aluminum pan receive double the heat?</h3>
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