Answer:
.0787 moles
Explanation:
I'm assuming you mean moles of gold present as the "amount."
This is a moles to moles calculation, so we set it up as such:
*Note that 15.5g Au is given to us, and 197 g / mol of Au is gold's molar mass.
15.5g Au * (1 mol Au / 197 g Au) = ?
We can evaluate the equation to get 15.5 / 197 to get .0787 moles of Au.
Answer:
Noble gases are non reactive
Explanation:
This is because they are thermodynamically very stable
Answer:
Explanation:
Sometimes weather is extreme, causing destruction and death. Too much rain can cause flooding. Too much hot weather for long periods of time without any rain can cause drought. Huge storms with strong winds, such as hurricanes and tornadoes, can do a great amount of damage to buildings and crops.
<em>hope this helps you~</em>
Answer:
Mode of transportation and source of energy
Energy sources are used in several major ways
Gasoline is used in cars, motorcycles, light trucks, and boats. Aviation gasoline is used in many types of airplanes. Distillate fuels are used mainly by trucks, buses, and trains and in boats and ships. Jet fuel is used in jet airplanes and some types of helicopters.
Explanation:
Let's investigate the substances involved in the reaction first. The compound <span>CH3NH3+Cl- is a salt from the weak base CH3NH2 and the strong acid HCl. When this salt is hydrated with water, it will dissociate into CH3NH2Cl and H3O+:
CH3NH3+Cl- + H2O </span>⇒ CH3NH2Cl + H3O+
Nest, let's apply the ICE(Initial-Change-Equilibrium) table where x is denoted as the number of moles used up in the reaction:
CH3NH3+Cl- + H2O ⇒ CH3NH2Cl + H3O+
Initial 0.51 0 0
Change -x +x +x
-------------------------------------------------------------------------------
Equilibrium 0.51 - x x x
Then, let's find the equilibrium constant of the reaction. Since the reaction is hydrolysis we use KH, which is the ratio of Kw to Ka or Kb. Kw is the equilibrium constant for water hydrolysis which is equal to 1×10⁻¹⁴. Since the salt comes from the weak base, we use Kb. Since pKb = 3.44, then. 3.44 = -log(Kb). Thus, Kb = 3.6307×10⁻⁴
KH = Kw/Kb = (x)(x)/(0.51 - x)
1×10⁻¹⁴/ 3.6307×10⁻⁴ = x²/(0.51-x)
x = 3.748×10⁻⁶
Since x from the ICE table is equal to the equilibrium concentration of H+, we can find the pH of the aqueous solution:
pH = -log(H+) = -log(x)
pH = -log ( 3.748×10⁻⁶)
pH = 5.43