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Inessa05 [86]
3 years ago
11

Where is .25, .5, and .75, on a graph?

Mathematics
1 answer:
STALIN [3.7K]3 years ago
8 0
Before the 1 on the x-axis
You might be interested in
Kindly solve this question
Dmitry_Shevchenko [17]

Answer:

x=-1/7

Step-by-step explanation:

\frac{3x-1}{3} -\frac{2x}{x-1} =x

\frac{(3x-1)(x-1)}{3x-3} -\frac{2x(3)}{3x-3} =x

\frac{3x^2-4x+1}{3x-3} -\frac{6x}{3x-3} =x

\frac{3x^2-10x+1}{3x-3} =x

\frac{3x^2-10x+1}{3x-3} =\frac{x(3x-3)}{3x-3}

\frac{3x^2-10x+1}{3x-3} =\frac{3x^2-3x}{3x-3}

3x^2-10x+1=3x^2-3x

-10x+1=-3x

-7x=1

x=-1/7

3 0
2 years ago
Henry draws an obtuse triangle how many obtuse angles does Henry's triangle have? Please eye help
Travka [436]
The sum of all three angles in any triangle is always 180 degrees. So in obtuse triangle there is only one obtuse angle (more than 90 degrees). If we have for example an obtuse angle of 91 degrees, then two other angles have to fit in 89 degrees which makes it impossible for any of them to be obtuse.
8 0
3 years ago
If the diagonal of a square is approximately 12.73, what is the length of its sides?
Alja [10]

Answer:

The length of the sides of the square is 9.0015

Step-by-step explanation:

Given

The diagonal of a square = 12.73

Required

The length of its side

Let the length and the diagonal of the square be represented by L and D, respectively.

So that

D = 12.73

The relationship between the diagonal and the length of a square is given by the Pythagoras theorem as follows:

D^{2} = L^{2} + L^{2}

Solving further, we have

D^{2} = 2L^{2}

Divide both sides by 2

\frac{D^{2}}{2} = \frac{2L^{2}}{2}

\frac{D^{2}}{2} = L^2

Take Square root of both sides

\sqrt{\frac{D^{2}}{2}} = \sqrt{L^2}

\sqrt{\frac{D^{2}}{2}} = L

Reorder

L = \sqrt{\frac{D^{2}}{2}}

Now, the value of L can be calculated by substituting 12.73 for D

L = \sqrt{\frac{12.73^{2}}{2}}

L = \sqrt{\frac{162.0529}{2}}

L = \sqrt{{81.02645}

L = 9.001469325

L = 9.0015 (Approximated)

Hence, the length of the sides of the square is approximately 9.0015

7 0
3 years ago
How can you tell from the equation of a rational function if the function has a hole in the graph ( a removable discontinuity) a
Eva8 [605]

Consider that,

x^2+4x+4 = (x+2)(x+2)

x^2+7x+10 = (x+2)(x+5)

Dividing those expressions leads to

(x^2+4x+4)/(x^2+7x+10) = (x+2)/(x+5)

The intermediate step that happened is that we have (x+2)(x+2) all over (x+2)(x+5), then we have a pair of (x+2) terms cancel as the diagram indicates (see below). This is where the removable discontinuity happens. Specifically when x = -2. Plugging x = -2 into (x+2)/(x+5) produces an output, but it doesn't do the same for the original ratio of quadratics. So we must remove x = -2 from the domain.

5 0
2 years ago
a family originally bought a home for $273,830. Now the home’s value is 30% higher than that. What is the value of the home now?
gavmur [86]

$355,394

100% +30% = 130% = 1.3

5 0
2 years ago
Read 2 more answers
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