The ship sails at 20 km / h.
So
20 km / h x 2 h = 40 km
The boat moves 40 km to the northeast.
Then, in the same way:
20 km / h x 1 h = 20 km.
The ship moves 20 km northwest.
We solve this problem using vectors. In this case, we must perform the sum of two vectors a and b
a) magnitude = 40 km and direction 20 degrees east
b) magnitude = 20 km and direction 10 degrees northwest
In Cartesian coordinates, these vectors are written as:
a) 40sin (20º) i + 40cos (20º) j = 13,68i + 37,59j
b) -20sin (10th) i + 20cos (10th) j = -3,473i + 19,70j
The displacement vector of the ship would be the sum of a + b
a + b = 10,207i + 57,29j Finally, the magnitude of the a + b vector will tell us how far the ship is
√(10.21² + 57.29²) = 58.92km
Answer:
Its 9 :)
Step-by-step explanation:
The answer to 3 3/16 divided by 3/8 is 8 1/2. This is because you have to turn the mixed number into an improper fraction and then divide by the method of keep change flip in order to get your answer
7. 65 + 75 = 140
180 - 140 = 40
( I think this is the answer)
ANSWER:30/48
multiply both numerator and denominator by 2
