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Andreyy89
2 years ago
13

Which graph represents and exponential function?

Mathematics
1 answer:
Sati [7]2 years ago
3 0

Answer:

Velocity time graph represent and exponential function

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What is the simplified value of the exponential expression 27 1/3?<br> 1/3<br> 1/9<br> 3<br> 9
madreJ [45]

Answer:

Step-by-step explanation:

27^1/3

27 is cube root of 3

so it can also be written as (3)^3

∴ {(3)^3}^1/3

3 and 3 will get cancelled

so it will be 3^1

= 3

8 0
3 years ago
How does Reflection work in real-life situations?
bazaltina [42]

Answer:

reflection is defined as the change in the direction of a wavefront at the interface between two different media, bouncing the wavefront back into the original medium. A common example of reflection is reflected light from a mirror or a still pool of water, but reflection affects other types of waves beside light.

Step-by-step explanation:

3 0
2 years ago
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Explain why all linear angle pairs must be supplementary, but all supplementary angles do not have to be linear pairs?
dimulka [17.4K]
Two angles are supplementary if their measures sum 180°.

Linear angle pairs are adjacent angles (they are together) and they form a straight angle, which is 180°. Therefore, they are supplementary.

But two angles may be separated and yet add 180°, then they are supplementary but are not linear angle pairs.
4 0
3 years ago
An airplane can ascend at a rate of 54 1/2 meters 2/3 of a second. how many meters can the airplane acend in one second
RideAnS [48]
The answer is 81.75. 54 1/2 divided by 2/3
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3 years ago
Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.
liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

f(x) = \frac{x^2+4x+3}{x^2-x-2}

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial x^2-x-2

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

(x-2) (x + 1)

We do the same with the numerator

x^2+4x+3

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

(x+3)(x + 1)

Therefore

f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}

Note that \frac{(x+1)}{(x+1)}=1 only if x \neq -1

So since x = -1 is not included in the domain the function has a discontinuity in x = -1

3 0
3 years ago
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