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Sergio039 [100]
3 years ago
7

Explain how to write 1.25 times 10 to the negative third power in standard form

Mathematics
1 answer:
OleMash [197]3 years ago
8 0
This is called "Scientific Notation"

1.25 \times {10}^{ - 3}
So you will always see the 10... Don't worry about it but worry if it is negative or positive because the sign will determine how to move the decimal point.

So, since it is negative then we will be moving the decimal point to the left. And, if it was a positive 3 then we'd move the decimal point to the right!

We will be moving it to the left "3" times because it says - 3 not - 5, etc...
1.25 \times {10}^{ - 3} = 0.00125
So just move the decimal 3 times in this case and there you go, your standard form. I forgot what the other form is but I can still solve for it...

I hope this helped if you have any questions then feel free to ask!!
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Simplify (8^4/10^4)^-1/4using rational exponents
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Answer:

   (\frac{8^4}{10^4} )^{-\frac{1}{4} }  = \frac{5}{4}

Step-by-step explanation:

<u><em>Explanation</em></u>

Given  

       (\frac{8^4}{10^4} )^{-\frac{1}{4} }

By using algebra formulas

  (\frac{a}{b} )^{m} = \frac{a^m}{b^n}

(\frac{8^4}{10^4} )^{-\frac{1}{4} } = \frac{(8^{4})^{\frac{-1}{4} }  }{(10^{4} )^{\frac{-1}{4} } }

(a^{m} )^{n} = a^{mn}

\frac{(8^{4})^{\frac{-1}{4} }  }{(10^{4} )^{\frac{-1}{4} } } = \frac{8^{4X\frac{-1}{4} } }{10^{4 X\frac{-1}{4} } }

          = \frac{8^{-1} }{10^{-1} }

           = \frac{10}{8} \\= \frac{5}{4}

<u><em>Final answer:-</em></u>

 (\frac{8^4}{10^4} )^{-\frac{1}{4} }  = \frac{5}{4}

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