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2 years ago

What is the x-intercept of a parabola also called

Mathematics

1 answer:

aliya0001 [1]2 years ago

7 0

Answer:

maximum point

Step-by-step explanation:

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Find the area of the figure. PLEASE HELP I NEED IT URGENT PLEASE

ale4655 [162]

Answer:

Area = Area of bigger triangle - Area of small triangle

${ \rm{area = ( \frac{1}{2} \times b_{b} \times h_{b}) - ( \frac{1}{2} \times b_{s} \times h _{s} )}} \\ \\ { \tt{area = ( \frac{1}{2} \times 18 \times 7) - ( \frac{1}{2} \times (18 - 13) \times 7) }} \\ \\ { \tt{area = (9 \times 7) - (2.5 \times 7)}} \\ \\ { \underline{ \tt{ \: \: area = 45.5 \: \: sq \: units \: \: }}}$

Area = area of square + area of two right angled triangles

${ \tt{area = (s \times s) + 2( \frac{1}{2} \times b \times h)}} \\ \\ { \tt{area = (6 \times 10) + (3 \times 5)}} \\ \\ { \underline{ \tt{ \: \: area = 75 \: \: {m}^{2} \: \: }}}$

5 0

1 year ago

Read 2 more answers

Please please help<br><br> ‼️WILL MARK BRAINLIEST‼️<br><br> 10 Points

asambeis [7]

B is the right answer.

4 0

3 years ago

fter production, a computer component is given a quality score of A, B, and C. On the average U of the components were given a q

RoseWind [281]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

In the given question some of the data is missing so, its correct question is defined in the attached file please find it.

Let

A is quality score of A

B is quality score of B

C is quality score of C

$\to P[A] =0.55\\\\\to P[B] =0.28\\\\\to P[C] =0.17\\$

Let F is a value of the content so, the value is:

$\to P[\frac{F}{A}] =0.15\\\\\to P[\frac{F}{B}] =0.12\\\\\to P[\frac{F}{C}] =0.14\\$

Now, we calculate the tooling value:

$\to p[\frac{C}{F}]$

using the baues therom:

$\to p[\frac{C}{F}] = \frac{p[C] \times p[\frac{F}{C} ]}{p[A] \times p[\frac{F}{A}] + p[B] \times p[\frac{F}{B}]+p[C] \times p[\frac{F}{C}] }$

$= \frac{ 0.17 \times 0.14 }{0.55 \times 0.15 + 0.28 \times 0.12 + 0.17 \times 0.14 } \\\\= \frac{0.0238}{0.0825 + 0.0336 + 0.0238} \\\\= \frac{0.0238}{0.1399} \\\\=0.1701$

7 0

3 years ago

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

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3 years ago

If 2x-3(x+4)=-5 then x=

Mrrafil [7]

2x - 3(x + 4) = -5
2x - 3x - 12 = -5
-x - 12 = -5
-x = -5 + 12
-x = 7
x = -7

The answer is: x = -7.

5 0

2 years ago

What is the x-intercept of a parabola also called​

What is the x-intercept of a parabola also called