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Ksju [112]
2 years ago
7

How do you solve 9r=3r+6

Mathematics
2 answers:
Lesechka [4]2 years ago
7 0
9r=3r+6
Subtract 3r from both sides
6r=6
Divide both sides by 6
r=1
Anettt [7]2 years ago
4 0

Answer:

r=1

Step-by-step explanation:

9r=3r+6  

-3r -3r

6r=6

/6  /6

r=1

Check your answer:

9(1)=3(1)+6

9=9 ✔️

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A rectangle has a perimeter of 30 inches if the width is 3 times it’s length find it dimension
kakasveta [241]

Answer:

Length = 11.25 and width = 3.75 inches.

Step-by-step explanation:

You must mean that the length is 3 times its width.

If the the width is x then the length is 3x inches.

Perimeter = 2*length + 2*width.

2(3x) + 2x = 30

6x + 2x = 30

8x = 30

x = 3.75.

3x = 11.25.

7 0
3 years ago
Which is the correct answer? A , B , C , or D?
NeX [460]

Answer:

A

Step-by-step explanation:

f(x) - g(x)

= x² - 8 - (4 - x) ← distribute parenthesis by - 1

= x² - 8 - 4 + x ← collect like terms

= x² + x - 12 → A

4 0
3 years ago
Which operation should you perform last in the expression 12 × 4^2?
drek231 [11]

Answer:

Multiplication

Step-by-step explanation:

Follow GEMDAS or PEMDAS. I would recommend GEMDAS. GEMDAS stands for Grouping symbols, exponents, multiply, divide, addition, subtraction. GO form the order G to S

3 0
2 years ago
(02.09) Given a triangle with vertices at points (4, 4), (4, 1), and (2, 1), which set of ordered pairs represents the new verti
wel
Hello!

This triangle is currently located in Quadrant 1. If it is rotated 90 degrees counter-clockwise around the origin, it will end up in Quadrant 2. The formula for this is seen below.

(x,y)⇒(-y,x)

We will do this to each point and get our final points.

(4,4)⇒(-4,4)
(4,1)⇒(-1,4)
(2,1)⇒(-1,2)

Therefore, the final points of our rotated triangle are (-4,4), (-1,4) and (-1,2).

I hope this helps!


4 0
3 years ago
What is the inverse of x^2-4x+5
lisabon 2012 [21]

we are given

f(x)=x^2-4x+5

Since, we have to find inverse of this function

step-1: we set f(x)=y

y=x^2-4x+5

step-2: switch x and y

x=y^2-4y+5

step-3: Solve for y

y^2-4y+(5-x)=0

now, we can use quadratic formula

y=\frac{4+\sqrt{4^2-4(5-x)} }{2}

f^{-1}(x)=\sqrt{x-1}+2

or

f^{-1}(x)=-\sqrt{x-1}+2..............Answer

6 0
3 years ago
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