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Ksju [112]
1 year ago
7

How do you solve 9r=3r+6

Mathematics
2 answers:
Lesechka [4]1 year ago
7 0
9r=3r+6
Subtract 3r from both sides
6r=6
Divide both sides by 6
r=1
Anettt [7]1 year ago
4 0

Answer:

r=1

Step-by-step explanation:

9r=3r+6  

-3r -3r

6r=6

/6  /6

r=1

Check your answer:

9(1)=3(1)+6

9=9 ✔️

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Answer:

m=-3

Step-by-step explanation:

10=7-m

m=7-10=-3

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What is probability? Can you give an example?
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Step-by-step explanation:

We can calculate probability by looking at the outcomes of an experiment or by reasoning about the possible outcomes.

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In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en
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Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in  Swahili language

n(S) = 125

The probability that the fluent in  Swahili language

P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in  English language

P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9

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The probability that the fluent in  English and Swahili

P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633

<u><em>Step(ii):</em></u>-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

           = 0.833+0.9-0.633

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<u><em>Final answer:-</em></u>

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

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