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3 years ago

Which statements accurately describe the rock cycle? Check all that apply

Chemistry

2 answers:

babymother [125]3 years ago

7 0

Answer: Correct Answer: number 3 and 4

Explanation:

Number 1: Incorrect: not any type of rock can be formed by only weathering and erosion, as we can see in the image. igneous rock and metamorphic rock are formed by melting, cooling and pressure processes.

Number 2: Incorrect: There is not a define order how rocks are formed, as you can see in the image, they can be formed from one or from the other, depending of the conditions that they are sumitted.

Number 3: Correct: Rock change too slowly over time, from a few million to hundreds of millions of years.

Number 4: Correct : The rock cycle shows how the three rocks relate to one another as you can see in the image.

Number 5: Incorrect: Rocks don´t last forever, because they are subdued to climate conditions constantly.

xxMikexx [17]3 years ago

6 0

Answer:

1, 3, 4

Explanation:

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Explain why the atomic mass of an element is usually not given as a whole number even though each individual atom of the element

Zinaida [17]

An atomic mass is the sum of the protons and neutrons of a given element. The atomic mass is given it what is called a weighted average of all the different kinds of that element. Take carbon for example. It has carbon-12, carbon-13, and carbon-14. The reason its atomic weight is so close to 12 (12.011 ish) is because carbon-12 is by far the most common, and carbon-13 and -14 are so uncommon, that the weighted average is close to 12, but not exactly 12.

7 0

4 years ago

Identify the effect of increasing acidity on the solubility of the given compounds.

Ilia_Sergeevich [38]

All the given compounds are basic on acidifying their solubility increases.

<u>Explanation:</u>

$C a_{3}\left(P O_{4}\right)_{2}$ solubility will increase, since it is basic in nature, on acidifying solubility increases.
$F e S$ being basic on acidification, the solubility increases.
$M g C O_{3}$ is alkaline in nature, it gets neutralized and there is no increase in acidity.
$M g B r_{2}$ is a salt and it shows no effect on acidification.
$A g I$ is a salt but insoluble in water and shows no effect on acidification.
$M g(O H)_{2}$ is strongly basic in nature, on acidifying the solubility increases.

4 0

4 years ago

Refer to the picture given below to give the answer. Don’t forget to use the correct amount of sig figs.

kumpel [21]

Answer:

9.62 μm

Explanation:

From the question given above, the following data were obtained:

Frequency (f) = 31.2 THz

Wavelength (λ) =..?

Next, we shall convert 31.2 THz to Hz.

This can be obtained as follow:

Recall:

1 THz = 1×10¹² Hz

Therefore,

31.2 THz = 31.2 THz × 1×10¹² Hz / 1 THz

31.2 THz = 3.12×10¹³ Hz

Therefore, 31.2 THz is equivalent to 3.12×10¹³ Hz.

Finally, we shall determine the wavelength (λ) infrared radiation as follow:

Frequency (f) = 3.12×10¹³ Hz.

Velocity (v) = 3×10⁸ m/s

Wavelength (λ) =..?

V = λf

3×10⁸ = λ × 3.12×10¹³

Divide both side by 3.12×10¹³

λ = 3×10⁸ / 3.12×10¹³

λ = 9.62×10¯⁶ m

Converting 9.62×10¯⁶ m to micro metre (μm) we have:

1 m = 1×10⁶ μm

Therefore,

9.62×10¯⁶ m = 9.62×10¯⁶ m × 1×10⁶ μm / 1 m

9.62×10¯⁶ m = 9.62 μm

Therefore, the wavelength of the infrared radiation is 9.62 μm

7 0

3 years ago

Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample

goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=2:2=1:1$

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

$n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol$

Similarly, number of moles of oxygen will be:

$n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol$

The ratio of number of moles of carbon and oxygen will be:

$C:O=n_{C}:n_{O}=3:3=1:1$

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.

4 0

3 years ago

Filtering air to remove dust and pollen is it chemical or physical change

Cerrena [4.2K]

Answer:

Physical Change

Explanation:

Because the filter is removeing the dust by having the air go though a thin material.

Hope it helps!

3 0

3 years ago