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katrin2010 [14]
2 years ago
8

The first plants to grow after a fire are called?

Chemistry
2 answers:
ELEN [110]2 years ago
8 0

Answer:

ephemeral

Explanation:

neonofarm [45]2 years ago
6 0

Answer:

Ephemerals

Explanation:

The first plants to move into the new bare ground after a wildfire are wildflowers or “weeds.” These fast-germinating, leafy herbaceous plants are also known as “forbs” or “ephemerals.” They quickly germinate, grow and produce a new crop of seeds.

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5Br−+BrO3−+6H+→3Br2+3H2O
sashaice [31]

Explanation :

The balanced chemical reaction is,

5Br^-+BrO_3^-+6H^+\rightarrow 3Br_2+3H_2O

The expression for the rates of consumption of the reactants are:

The rate of consumption of Br^- = -\frac{1}{5}\frac{d[Br^-]}{dt}

The rate of consumption of BrO_3^- = -\frac{d[BrO_3^-]}{dt}

The rate of consumption of H^+ = \frac{1}{6}\frac{d[H^+]}{dt}

The expression for the rates of formation of the products are:

The rate of consumption of Br_2 = +\frac{1}{3}\frac{d[Br_2]}{dt}

The rate of consumption of H_2O = +\frac{1}{3}\frac{d[H_2O]}{dt}

5 0
2 years ago
Select the most acidic solution from these options. select the most basic (alkaline) solution from these options. select the lea
Gala2k [10]
Most acidic: solution B, pH = 1
Most Basic: solution C, pH = 13
Least acidic: solution A, pOH = 1
8 0
2 years ago
Read 2 more answers
If z = 4.0 and y = 9.6, what is the value of x?
krok68 [10]

Answer:

The value of x will be "1.4".

Explanation:

The given values are:

y = 9.6

z = 4.0

As we know,

The relation between x, y and z is:

⇒ z = \frac{y}{x}

and,

⇒ x=\frac{y}{z}

On substituting the given values, we get

⇒    =\frac{5.6}{4.0}

⇒    =1.4

8 0
3 years ago
What was the result of collisions between the early Earth and other, smaller protoplanets?
RoseWind [281]

The trajectory of their motion knocked the Earth into a different orbit.

3 0
3 years ago
Consider the following mechanism for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution. H+ + H2O2 ? H3
Margarita [4]

<u>Answer:</u> The rate law for the reaction is \text{Rate}=k'[H+][H_2O_2][Br^-]

<u>Explanation:</u>

Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

The chemical equation for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution follows:

2H^++2Br^-+H_2O_2\rightarrow Br_2+2H_2O

The intermediate reaction of the mechanism follows:

<u>Step 1:</u>  H^++H_2O_2\rightleftharpoons H_3O_2^+;\text{ (fast)}

<u>Step 2:</u>  H_3O_2^++Br^-\rightarrow HOBr+H_2O;\text{(slow)}

<u>Step 3:</u>  HOBr+H^++Br^-\rightarrow Br_2+H_2O;\text{(fast)}

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

\text{Rate}=k[H_3O_2^+][Br^-]          ......(1)

As, [H_3O_2^+] is not appearing as a reactant in the overall reaction. So, we apply steady state approximation in it.

Applying steady state approximation for [H_3O_2^+] from step 1, we get:

K=\frac{[H_3O_2^+]}{[H^+][H_2O_2]}  

[H_3O_2^+]=K[H^+][H_2O_2]

Putting the value of [H_3O_2^+] in equation 1, we get:

\text{Rate}=k.K[H^+][H_2O_2][Br^-]\\\\\text{Rate}=k'[H+][H_2O_2][Br^-]

Hence, the rate law for the reaction is \text{Rate}=k'[H+][H_2O_2][Br^-]

4 0
3 years ago
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