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katrin2010 [14]
2 years ago
8

The first plants to grow after a fire are called?

Chemistry
2 answers:
ELEN [110]2 years ago
8 0

Answer:

ephemeral

Explanation:

neonofarm [45]2 years ago
6 0

Answer:

Ephemerals

Explanation:

The first plants to move into the new bare ground after a wildfire are wildflowers or “weeds.” These fast-germinating, leafy herbaceous plants are also known as “forbs” or “ephemerals.” They quickly germinate, grow and produce a new crop of seeds.

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For example, this quote states that "Switches are key building blocks for any network. They connect multiple devices, such as computers, wireless access points, printers, and servers; on the same network within a building or campus. A switch enables connected devices to share information and talk to each other."

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3 years ago
A word of equationn for the reacyion between lithium and water
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3 years ago
True or false: potential energy increases as like charges get closer to one another
Veronika [31]
True, is the correct answer.
3 0
2 years ago
Which historical era was marked the beginnings of European explorations, conquests of the Americas, trans-Atlantic slave trade a
Tomtit [17]

Answer : Option C) Early modern era


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8 0
2 years ago
A first-order reaction is 45% complete at the end of 43 minutes. What is the length of the half-life of this reaction
shtirl [24]

The half-life of the reaction is 50 minutes

Data;

  • Time = 43 minutes
  • Type of reaction = first order
  • Amount of Completion = 45%

<h3>Reaction Constant</h3>

Let the initial concentration of the reaction be X_0

The reactant left = (1 - 0.45) X_0 = 0.55 X_0 = X

For a first order reaction

\ln(\frac{x}{x_o}) = -kt\\ k = \frac{1}{t}\ln (\frac{x_o}{x}) \\ k = \frac{1}{43}\ln (\frac{x_o}{0.55_o})\\ k = 0.013903 min^-^1

<h3>Half Life </h3>

The half-life of a reaction is said to be the time required for the initial amount of the reactant to reach half it's original size.

x = \frac{x_o}{2} \\t = t_\frac{1}{2} \\t_\frac{1}{2} = \frac{1}{k}\ln(\frac{x_o}{x_o/2})\\

Substitute the values

t_\frac{1}{2} = \frac{1}{k}\ln(2)=\frac{0.6931}{0.013903}\\t_\frac{1}{2}= 49.85 min = 50 min

The half-life of the reaction is 50 minutes

Learn more on half-life of a first order reaction here;

brainly.com/question/14936355

4 0
2 years ago
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