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-Dominant- [34]
4 years ago
6

Which events occurred during the space race

Chemistry
2 answers:
Roman55 [17]4 years ago
8 0

Answer:

Date Significance Soviet Union Mission

August 21, 1957 First intercontinental ballistic missile (ICBM) R-7 Semyorka

October 4, 1957 First artificial satellite First signals from space Sputnik 1

November 3, 1957 First dog in orbit (Laika) Sputnik 2

January 31, 1958 First US satellite, detection of Van Allen radiation belts

Explanation:

kupik [55]4 years ago
4 0

Answer:

NASA was established in 1958.

Explanation:

You might be interested in
For KNO3 the heat of solution is 23.8 kJ/mol and the lattice energy is -685.0 kJ/mol. Calculate the heat of hydration.
alisha [4.7K]

<u>Answer:</u> The heat of hydration for potassium nitrate is 708.8 kJ/mol

<u>Explanation:</u>

We are given:

Heat of solution for potassium nitrate = 23.8 kJ/mol

Lattice energy for potassium nitrate = -685.0 kJ/mol

Heat of hydration for potassium nitrate = ?

To calculate the heat of hydration, we use the equation:

Heat of the solution = Heat of hydration + Lattice energy

Putting values in above equation, we get:

23.8=\text{Heat of hydration}+(-685.0)\\\\\text{Heat of hydration}=23.8-(-685.0)\\\\\text{Heat of hydration}=708.8kJ/mol

Hence, the heat of hydration for potassium nitrate is 708.8 kJ/mol

6 0
3 years ago
When potassium hydroxide and barium chloride react, potassium chloride and barium hydroxide are formed. The balanced equation fo
Mashcka [7]

Answer:

The answer to your question is letter C.

Explanation:

Reaction

Potassium hydroxide = KOH

Barium chloride = BaCl₂

Potassium chloride = KCl

Barium hydroxide = Ba(OH)₂

           KOH   +   BaCl₂    ⇒    KCl   +   Ba(OH)₂

         Reactant        Elements       Products

               1                     K                      1

               1                     Ba                    1

               2                    Cl                     1  

                1                     H                    2

                1                     O                    2

The reaction is unbalanced

        2KOH   +   BaCl₂    ⇒   2KCl   +   Ba(OH)₂

         Reactant        Elements       Products

               2                     K                     2

               1                     Ba                    1

               2                    Cl                     2  

               2                      H                    2

               2                     O                    2

Now, the reaction is balanced

7 0
3 years ago
Read 2 more answers
If moles of solute does not change throughout the dilution process, then what mathematical relationship can you formulate about
Firlakuza [10]

Answer:

Explanation:

Often, a worker will need to change the concentration of a solution by changing the amount of solvent. Dilution is the addition of solvent, which decreases the concentration of the solute in the solution. Concentration is the removal of solvent, which increases the concentration of the solute in the solution. (Do not confuse the two uses of the word concentration here!)

In both dilution and concentration, the amount of solute stays the same. This gives us a way to calculate what the new solution volume must be for the desired concentration of solute. From the definition of molarity,

molarity = moles of solute / liters of solution

we can solve for the number of moles of solute:

moles of solute = (molarity)(liters of solution)

A simpler way of writing this is to use M to represent molarity and V to represent volume. So the equation becomes

moles of solute = MV

Because this quantity does not change before and after the change in concentration, the product MV must be the same before and after the concentration change. Using numbers to represent the initial and final conditions, we have

M1V1 = M2V2

as the dilution equation. The volumes must be expressed in the same units. Note that this equation gives only the initial and final conditions, not the amount of the change. The amount of change is determined by subtraction

3 0
3 years ago
How many milliliters of 2.5 M HCl are required<br> to exactly neutralize 1.5 L of 5.0 M NaOH?
Airida [17]

Answer:

3000mL

Explanation:

The following data were obtained from the question:

Volume of acid (Va) =..?

Molarity of acid (Ma) = 2.5M

Volume of base (Vb) = 1.5L

Molarity of base (Mb) = 5M

Next, we shall write the balanced equation for the reaction. This is given below:

HCl + NaOH —> NaCl + H2O

From the balanced equation above,

We obtained the following:

Mole ratio of the acid (nA) = 1

Mole ratio of base (nB) = 1

Next, we shall determine the volume of HCl needed for the reaction. This can be obtained as follow illustrated below:

MaVa / MbVb = nA/nB

2.5 x Va / 5 x 1.5 = 1

Cross multiply

2.5 x Va = 5 x 1.5

Divide both side by 2.5

Va = 5 x 1.5 / 2.5

Va = 3L

The volume of the acid required is 3L.

Finally, we shall convert the volume of the acid from litre (L) to millilitre (mL). This is illustrated below:

1L = 1000mL

Therefore, 3L = 3 x 1000 = 3000mL.

Therefore, the volume of the acid, HCl in mL needed fi4 the reaction is 3000mL

7 0
4 years ago
Which has a higher boiling point hcl or hi
Likurg_2 [28]

HI.

Hope this helps!

-Payshence

3 0
3 years ago
Read 2 more answers
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