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joja [24]
3 years ago
8

In a group of 25 factory workers, 20 are low-risk and five are high-risk. two of the 25 factory workers are randomly selected wi

thout replacement. calculate the probability that exactly one of the two selected factory workers is low-risk.
Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0
Let
L=event that a selected worker has low risk
H=event that a selected worker has high risk

We need to find
P(HL)+P(LH)
=5*20/(25*24)+20*5/(25*24)
=1/6+1/6
=1/3
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Answer:

(0, 1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
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<u>Step 1: Define Systems</u>

y + 5x = 1

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<u>Step 2: Rewrite Systems</u>

y + 5x = 1

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<u>Step 3: Redefine Systems</u>

y = 1 - 5x

5y - x = 5

<u>Step 4: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitution in <em>y</em>:                      5(1 - 5x) - x = 5
  2. Distribute 5:                             5 - 25x - x = 5
  3. Combine like terms:                5 - 26x = 5
  4. Isolate <em>x</em> term:                          -26x = 0
  5. Isolate <em>x</em>:                                   x = 0

<u>Step 5: Solve for </u><em><u>y</u></em>

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  2. Substitute in <em>x</em>:                       5y - 0 = 5
  3. Subtract:                                 5y = 5
  4. Isolate <em>y</em>:                                 y = 1
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