9. One newton equals about 100 g

Solve for w, x, and y. Show your work.

sveta [45]

First of all, the left triangle is an equilateral triangle. Which means that all the interior angles are 60 degrees.

4w=60

w=15

Then all 3 sides are equal thus we can set up equation 3x-y=4y then simplify,

3x=5y

Going to the triangle on the right its isosceles we can set up equation 2x+50=180

2x=130

x=75

Substitute this back into equation above 3x=5y

5y=3*75

y=45

Therefore

x=75

y=45

w=15

Done!

5 0

3 years ago

Plss view the image :((((((((((

topjm [15]

Answer:

f(x) = -8

Step-by-step explanation:

f(x) = x² + 2x – 8

f(x) = (-2)² + 2(-2) – 8

f(x) = 4 + (-4) – 8

f(x) = 4 – 4 – 8

f(x) = 0 – 8

f(x) = -8

I hope this helps

8 0

3 years ago

Select the correct answer. Which expression is an equivalent expression of 12x + 10 + 4y? 2(6x + 2y + 6) 3(4x + y + 10) 2(6x + 4

Illusion [34]

The answer would be 2(6x+5+2y) you can figure this out through the distributive property. 2(6x)=12x 2(5)=10 and 2(2y)= 4y this would reult in giving you the equation 12x+10+4y

4 0

3 years ago

A class contains 3 female and 9 male students. Find the probability that a student chosen at random is a male, and then a second

sammy [17]

9 +3 = 12 students

9 are male
1st = 9/12 = 3/4
2nd = 8/11

3/4 * 8/11 = 6/11

Answer = D) 6/11

8 0

3 years ago

Within a computer service company, 20 percent of the male employees and 30 percent of the female employees attend night school.

Maksim231197 [3]

26% of all the employees attend night school

Step-by-step explanation:

The given is:

Within a computer service company, 20 percent of the male employees and 30 percent of the female employees attend night school

40 percent of all employees are male

We need to find what percent of all the employees attend night school

Assume that the number of all employees is x

∵ The company has x employees

∵ 40 percent of all employees are male

- Find 40% of x

∵ 40% × x = $\frac{40}{100}$ × x = 0.4 x

∴ The number of the male employees is 0.4 x

- Subtract 0.4 x from x to find the number of the female employees

∵ The number of female employees = x - 0.4 x = 0.6 x

∴ The number of the female employees is 0.6 x

∵ 20 percent of the male employees attend night school

- Multiply 20% by 0.4 x to find the number of male employees

who attend night school

∴ The number of male who attend night school = 20% × 0.4 x

∴ The number of male who attend night school = $\frac{20}{100}$ × 0.4 x

∴ The number of male who attend night school = 0.08 x

∵ 30 percent of the female employees attend night school

- Multiply 30% by 0.6 x to find the number of female employees

who attend night school

∴ The number of female who attend night school = 30% × 0.6 x

∴ The number of male who attend night school = $\frac{30}{100}$ × 0.6 x

∴ The number of male who attend night school = 0.18 x

Add the number of male and female who attend night school

∵ 0.08 x + 0.18 x = 0.26 x

∴ The number of male and female who attend night school is 0.26 x

- Find the percentage of 0.26 x of x

∵ $\frac{0.26x}{x}$ × 100% = 26%

∴ 26% of all the employees attend night school

26% of all the employees attend night school

Learn more:

You can learn more about the percentage in brainly.com/question/6871421

#LearnwithBrainly

5 0

3 years ago