Answer:
Raul's claims are not correct
The equation of the graph is 
Step-by-step explanation:
Part a)
we know that
The fact that the data form a straight line does not imply that it is a proportional relationship. In order for it to be a proportional relationship, in addition to the fact that a straight line must be formed, it must pass through the origin.
In this problem the graph shows a proportional relationship because the data forms a straight line and passes through the origin (0,0)
therefore
The claim that the graph shows a proportional relationship because the data forms a straight line is not correct
Part B)
<u>Find the slope of the straight line</u>
Let
The formula to calculate the slope between two points is equal to
substitute the values
therefore
The claim that he reads 1.5 pages per minute is not correct
Part C)
The equation of the graph is equal to
X2+12x+35 should be written as <span>x^2+12x+35, where "^"
denotes exponentiation.
Since the coefficient of the x^2 term is 1, we can focus on 35, finding its factors. Note that 35 = 1*35, 5*7. Also note that 5+7 = 12.
Thus, </span>x^2+12x+35 can be re-written as (x+5)(x+7). As a check, multiply 5 and 7; you get 35, which matches the original <span>x^2+12x+35. Then add 5x to 7x, obtaining 12x, which also matches.</span>
Answer:
1 ft3= 0,028 m3
Step-by-step explanation:
We know that a 1 ft= 0,305 m,
if we cubed the above equation we have the following
1 ft3= (0,305)^3 m3
1 ft3= 0,028 m3
Answer:
Probability that at most 50 seals were observed during a randomly chosen survey is 0.0516.
Step-by-step explanation:
We are given that Scientists conducted aerial surveys of a seal sanctuary and recorded the number x of seals they observed during each survey.
The numbers of seals observed were normally distributed with a mean of 73 seals and a standard deviation of 14.1 seals.
Let X = <u><em>numbers of seals observed</em></u>
The z score probability distribution for normal distribution is given by;
Z = 
~ N(0,1)
where, 
= population mean numbers of seals = 73
= standard deviation = 14.1
Now, the probability that at most 50 seals were observed during a randomly chosen survey is given by = P(X 
50 seals)
P(X 50) = P( 
) = P(Z -1.63) = 1 - P(Z < 1.63)
= 1 - 0.94845 = <u>0.0516</u>
The above probability is calculated by looking at the value of x = 1.63 in the z table which has an area of 0.94845.
If RS arc is = to the RS central angle then the RS arc would be 20 degrees, but if the RS is on the Circumference then the RS arc would be 40.
