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Bumek [7]
3 years ago
15

Where would we find the point (–10,0)? A. Quadrant III B. y-axis C. Quadrant II D. x-axis

Mathematics
2 answers:
kaheart [24]3 years ago
7 0
D.) x-axis. Hope this helps (:
Elina [12.6K]3 years ago
4 0
The answer is D. x-axis, because of the layout of (x,y), meaning there would be an x value of -10, but no y value so it would sit on the x-axis
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Answer:

b) √29

Step-by-step explanation:

Given: The origin is (0, 0), the point P is (2, -5).

We need to use the distance formula.

Distance formula = \sqrt{(x2 -x1)^2 + (y2 - y1)^2} \\

Here x2 = 2, x 1 = 0, y1 =0, y2 = -5

Distance = \sqrt{(2 -0)^2 + (-5 - 0)^2}

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= √(4 + 25)

= √29

The answer is b) √29

Hope you will understand the concept.

Thank you.

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3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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