2c^5 + 44c^4 + 242c^3
Take out common factors.
= 2c^3(c^2 + 22c + 121)
( Refer for attachment for next step )
= 2c^3(c + 11)(c + 11)
= 2c^3(c + 11)^2
Answer:
Step-by-step explanation:
In this question, we're trying to make a new equation.
We know that:
- We translated 13 units down
When it says down, we know that the y intercept would be changing.
Since there werer no y intercept or beginning point to start with, we know that before we translated, it was at 0.
Since we went down 13 units, we're subtracting 13 units from our original spot.
This means that we're going down -13.
When you put that into an equation, it should look like this:
y= |x| - 13
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Because the Median could be anywhere within the interquartile range the upper quartile could be between 10 and 15
I think it is C. 60.
You can eliminate A because it is not a right angle, and D because the angle is bigger than the given angle. So it is between 50 and 60, and I hope this is right and the picture makes sense
6a+12=2(3a-8)
6a+12=6a-16
-12. -12
6a=6a-4
-6a -6a
0=-4
no solution because the equation is false.