We have to find the number of ways an employer send 3 employees to a job fair if she has 11 employees.
This is the problem from combination.
The formula for combination is given by

Here, n= 11, r= 3
Therefore, total number of ways is given by

A is the correct option.
<span>–vp + 40 < 95
-vp < 55
-vp < 55 / p
v > 55 / p</span>
Answer:
B 24
Step-by-step explanation:
3/5 is 54°
1/3 is 30°
54-30 = 24
Isosceles triangle because there are 2 angles that's the same.
*see attachment for the missing figure
Answer:
Angle ADE = 45°
Angle DAE = 30°
Angle DEA = 105°
Step-by-step explanation:
Since lines AD and BC are parallel, therefore:
Given that angle Angle CBE = 45°,
Angle ADE = Angle CBE (alternate interior angles are congruent)
Angle ADE = 45° (Substitution)
Angle DAE = Angle ACB (Alternate Interior Angles are congruent)
Angle ACB = 180 - 150 (angles on a straight line theorem)
Angle ACB = 30°
Since angle DAE = angle ACB, therefore:
Angle DAE = 30°
Angle DEA = 180 - (angle ADE + angle DAE) (Sum of angles in a triangle)
Angle DEA = 180 - (45 + 30) (Substitution)
Angle DEA = 180 - 75
Angle DEA = 105°