The pertinent formula is A = P (1 + r/n )^(nt), where
P is the original amount of money (Principal),
A is the compound amount,
r is the annual interest rate, expressed as a decimal fraction,
n is the # of compounding periods per year, and
t is the # of years.
Here, A = $35000 ( 1 + 0.04/4)^(4*6)
= $35000 (1.01)^24
= $35000 (1.2697) = $44440.71
5p - 3q = -39
- (-2p - 3q = 3)
==> 7p = -42 ==> p = -6
==> p = -6
-2(-6) - 3q = 3 ==> 12 - 3q = 3
==>p = -6
-3q = 3 - 12 ==> -3q = -9
==> p = -6
q = 3
Answer:
$250
Step-by-step explanation:
Let x = amount he started with in his drawer
x + $823.27 - $734.87 = $338.40
$823.27 would be added because it is money going in
$734.87 would be subtracted because it is the money going out
solve for x
x = $250
