4 years ago

Need help plz thanks will mark brainest

Mathematics

1 answer:

scoundrel [369]4 years ago

4 0

106.48 square inches.

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Look at the area models.

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4/10

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For which rational expressions is 8 an excluded value? Check all that apply.

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3 years ago

Use the law of cosines to solve the problem.on a baseball field, the pitcher's mound is 60.5 feet from home plate. during practi

34kurt

Answer: 169.26 feet.

Step-by-step explanation:

Here, The distance of pitcher's mound from the home plate = 60.5 feet

And, the distance covered by ball when it was hit by the bat = 216 feet

Let the outfielder throw the ball from the distance x feet.

Thus, by the below diagram,

$x^2=216^2+60.5^2-2\times 216\times 60.5\times cos(34^{\circ})$

$x^2=46656+3660.25-21667.7259963 =28648.5240037$

$\implies x = 169.258748677\approx 169.26\text{ feet}$

Hence, the outfielder throw the ball from the distance of 169.26 feet Approximately.

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4 years ago

10m3 of air weigh 13 kg. Chapter Reference c How much does the air weigh in a room 4.2m long, 3.5m wide, and 2.6m high?

Zarrin [17]

Answer:

The air weight in a room is 49.69 kg.

Step-by-step explanation:

It is given that the room is 4.2m long, 3.5m wide, and 2.6m high. It is also given that 10 m³ of air weigh 13 kg.

The formula to find the volume of cuboid is,

$V=l\times b\times h$

$V=4.2\times 3.5\times 2.6$

$V=38.22$

The volume of room is 38.22 m³.

Since it is given that, 10 m³ of air weigh 13 kg. So,

$1 m^3=\frac{13}{10}kg$

$1 m^3=1.3kg$

So the air weight in the room is,

$\text{Air weight}=1.3\times 38.22$

$\text{Air weight}=49.686\approx 49.69$

Therefore the air weight in a room is 49.69 kg.

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3 years ago

What does coordinates mean?

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Directions to a place, or point on a graph.

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