Midpoint of a segment whose endpoints are (x₁,y₁) and (x₂,y₂)
M((x₁+x₂)/2 , (y₁+y₂)/2)
1)
(3,7)
(7,3)
M( (3+7) /2 , (7+3)/2 )
M(10/2 , 10/2)
M(5,5)
B(5,5).
2)
Distance between the points (x₁,y₁) and (x₂,y₂)
Distance=√[(x₂-x₁)²+(y₂-y₁)₂]
(6,32)
(-8,-16)
distance=√[(-8-6)²+(-16-32)²]
d=√[(-14)²+(-48)²]
d=√(196+2304)
d=√2500
d=50
D. 50
(2,3)
(7,4)
d=√[(7-2)²+(4-3)²]
d=√(5²+1²)
d=√(25+1)
d=√26≈5.1
d≈5.1
16 = 1/4x + 2.5...where x stands for diameter of large gear
16 - 2.5 = 1/4x
13.5 = 1/4x....multiply both sides by 4, eliminating the 1/4 on the right side
13.5 * 4 = x
54 = x.....the large gear is 54 cm
Supplementary angles are 2 angles that add up to a total of 180°
Complementary angles are 2 angles that add up to a total of 90°
I hope this helps. If it does, please rate as Brainliest :D
