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3 years ago

Which type of triangle will always have a perpendicular bisector that is also an angle bisector?

Mathematics

2 answers:

jenyasd209 [6]3 years ago

8 0

Answer:

Equilateral triangle will always have a perpendicular bisector that is also an angle bisector.

Step-by-step explanation:

Equilateral triangle property:

All sides of the equilateral triangle are equal.
Angle of every equilateral triangle are equal to 60°.

Every altitude of an equilateral triangle is also a median and a bisector.
Each median is also an altitude and a bisector.
Each bisector is also an altitude and a median.

Therefore, by equilateral triangle property;

Perpendicular bisectors are angle bisectors in an equilateral triangle Since, all sides and angles are the same in an equilateral triangle.

Also, the angle bisector of an equilateral triangle forms 90 degree angle with the opposite side and bisects that side.

MariettaO [177]3 years ago

4 0

That would be an Equilateral Triangle.

Hope this helped! :))

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3 years ago

Rectangle A has length 12 and width 8. Rectangle B has length 15 and width 10. Rectangle C has length 30 and width 15. Is Rectan

sergeinik [125]

Rectangles are similar figures, thus if scaled copies of each other then the ratios of corresponding sides must be equal

compare ratios of lengths and widths

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k = $\frac{12}{15}$ = $\frac{4}{5}$ ← ratio of lengths

k = $\frac{8}{10}$ = $\frac{4}{5}$ ← ratio of widths

scale factors are equivalent, hence rectangle A is a scaled copy of B

rectangles C and B

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scale factors (k ) are not equal, hence C is not a scaled copy of B

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4 years ago

19) Which one of the following expressions has the greatest value?

astra-53 [7]

Answer:

Step-by-step explanation:

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3 years ago

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9514 1404 393

Answer:

1) f⁻¹(x) = 6 ± 2√(x -1)

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Step-by-step explanation:

In general, swap x and y, then solve for y. Quadratics, as in the first problem, do not have an inverse function: the inverse relation is double-valued, unless the domain is restricted. Here, we're just going to consider these to be "solve for ..." problems, without too much concern for domain or range.

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3) x = √(y +2) -4

x +4 = √(y +2) . . . . add 4

(x +4)² = y +2 . . . . square both sides

y = (x +4)² -2 . . . . . subtract 2

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6 0

3 years ago

Can someone help :))

katovenus [111]

Answer:

the first one, and the last one

Step-by-step explanation:

8 0

3 years ago