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Vladimir79 [104]
3 years ago
12

What is 0.06x10 to the 2 power

Mathematics
2 answers:
Brut [27]3 years ago
6 0
0.06 x 10 2 power this you can move the decimal twice to the right or you know 10x10=100 you can multiply 0.06 by 100 and you will still get 6 for both ways
jarptica [38.1K]3 years ago
6 0
3600 cuz u multply 60 x 60 and u get that
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The product of 21 and sum of -10​
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Answer:

11

Step-by-step explanation:

product 21 is 21

21+(-10)=11.

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https://telefoonreparatie.nl/telefoon-reparatie-waalwijk/

5 0
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4 0
3 years ago
3/4 and 9/19 a proportion
Zepler [3.9K]
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3 0
3 years ago
The circle with center O has a minor arc BSA with a length of
tangare [24]

Answer:

D. \frac{27\pi}{2} inches.

Step-by-step explanation:

We have been given that the circle with center O has a minor arc BSA with a length of 3\pi^{2} inches. The central angle is 40°.

To find the circumference of circle we will use formula:

\frac{\text{Central angle}}{2\pi}=\frac{\text{Arc length}}{2\pi r}, where 2\pi= measure of 360 degrees in radians and 2\pi r= circumference of circle.  

Let us convert measure of central angle into radians.                        

40^{o}=\frac{40*\pi}{180} =\frac{2\pi}{9}

Upon substituting our given value in the formula we will get,        

\frac{\frac{2\pi}{9}}{2\pi}=\frac{\frac{3\pi}{2}}{2\pi r}

\frac{2\pi}{18\pi}=\frac{3\pi}{4\pi r}    

\frac{1}{9}=\frac{3}{4r}      

Cross multiplying we will get,      

4r=27  

r=\frac{27}{4}

Hence, the radius of our circle is 27/4 inches.  

Since the circumference of circle is 2\pi r. Upon substituting  r=\frac{27}{4} we will get,

2\pi r=2\pi* \frac{27}{4}=\frac{27\pi}{2}

Therefore, circumference of our given circle will be \frac{27\pi}{2} inches and option D is the correct choice.

6 0
3 years ago
Please help will mark brainly
HACTEHA [7]

Answer: \sqrt{12} , \sqrt{\frac{49}{4} }, \frac{25}{7}, 3.6

Step-by-step explanation:

Root 12 = 3.46

25/7 = 3.57

3.6 = 3.6

and Root 49/Root 4 = 3.5

Simply order them from least to greatest from here. Hope this helps

6 0
3 years ago
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