Answer:
D) Abner can spend $60 per month on school clothes and $20 per month on gym clothes and stay within his budget.
Step-by-step explanation:
In the problem it states that Abner will spend 3 times more on (s)school clothes than (g) gym clothes.
So it would appear as s ≥ 3g.
If we plug in $60 as s (school clothes) and $20 as g (gym clothes), the statement is true.
60 ≥ 3(20)
60 ≥ 60. These numbers make the linear system true.
If you have trouble with this, an easy way to find this answer is simply creating the linear system that represents the problem, (he will buy 3 times more school clothes than gym clothes) s ≥ 3g and plug in each variable from the answer choices until you find the variables that make the linear system true.
I believe the answer would be 4 sorry if it’s wrong
Well, there isn’t really an end for numbers...
However; The biggest number referred to regularly is a googolplex (10googol), which works out as 1010^100. That isn’t the end to numbers but it is a huge one. We will replace that with ‘all the numbers in the world’.
106 is the exponent equivalent to 1 million
So your question would be:
106 x 1010^100 =
However I don’t believe there is a calculator that large.
Answer:
8x + 5
Step-by-step explanation:
5 * (2x+1) = 10x +5
10x + 5 -2x
8x + 5
