All categories

4 years ago

1. Check the divisibility of the following numbers by 2, 3, 9 and 11 a) 76543 b) 98765436

Mathematics

1 answer:

Alla [95]4 years ago

6 0

Answer:

1. ( I didnt understand the question but I divided them using the calculator.)

A.) 76543

÷ 2= 38,271.5

÷ 3= 25,514.333...

÷ 9= 8,504.777...

÷ 11= 6,958.454545...

B.) 98765436

÷ 2= 49,382,718

÷ 3= 32,921,812

÷ 9= 10,973,937.333...

÷ 11= 8,978,676

2. B

A.) 67894

÷ 4= 16,973.5

÷ 8= 8,486.75

B.) 9685048

÷ 4= 2,421,262

÷ 8= 1,210,631

Explanation:

I used the calculator to divide.

I hope this helps! I'm sorry if it's wrong.

You might be interested in

Which of the following numbers is irrational? Select all that apply.

MAXImum [283]

The square root of 15 and 3 are irrational because they are decimals and is not a whole number

4 0

2 years ago

Find x K (7x + 217 47 M

Butoxors [25]

Answer:

x=16

Step-by-step explanation:

The opposite angles will always be supplementary

<K + < M = 180

47+ 7x+21 = 180

Combine like terms

7x+68 = 180

Subtract 68

7x = 180-68

7x = 112

Divide by 7

7x/7 = 116/7

x =16

3 0

2 years ago

Find the distance using the modulus of the difference between z1 = -8 + 3i and z2 = 7 - 4i. Show all work for full credit.

3241004551 [841]

Answer:

$\sqrt{274}$

Step-by-step explanation:

Given $z_1=-8+3i,\ z_2=7-4i.$

1. Find the difference $z_1-z_2:$

$z=z_1-z_2=-8+3i-(7-4i)=-8+3i-7+4i=(-8-7)+(3i+4i)=-15+7i.$

This complex number has real part $Rez=-15$ and imaginary part $Imz=7.$

2. The modulus of complex number z is

$|z|=\sqrt{Re^2z+Im^2z}=\sqrt{(-15)^2+7^2}=\sqrt{225+49}=\sqrt{274}.$

5 0

4 years ago

Read 2 more answers

2x+3y=0 and x+2y=-1 Solve by substitution

dmitriy555 [2]

Answer:

The solution of the given equations is (-3,2)

Step-by-step explanation:

Step:1

The Given equations are 2 x+3 y=0 .......(1)

x+2 y-1 =0.........(2)

Step 2:-

Solving both equations by using substitution method

multiply equation (2) with number '2' ,

2 x+4 y-2=0.......(3)

subtracting the equations (1) and (3) and cancelled 'x' terms

we get $3y-4y=0-2$

$y=2$

Step 3:-

substitute y= 2 in equation (1) we get

$2 x+3 y=0$

$2 x+3(2)=0$

$2 x=-6$

$x=-3$

Final answer:-

The solution of the given equations is (-3,2)

8 0

4 years ago

HELP PLEASE

lozanna [386]

Answer:

i believe it's b:))

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers