<span>Ohm's law deals with the relation between
voltage and current in an ideal conductor. It states that: Potential difference
across a conductor is proportional to the current that pass through it. It is
expressed as V=IR.
V = IR
200 = 20R
R = 10 ohms</span>
Answer:C:Less than 45 centimeters, as the ball transforms some of its potential energy into thermal energy and sound energy
Less than 45 centimeters, as the ball transforms some of its potential energy into thermal energy and sound energy.
Although the initial energy (potential energy is preserved), the energy of deformation as the ball strikes a surface creates energy dissipation in the form of frictional heat and audible sound energy.
Every time the ball bounces, its height will be less than its previous height.
Explanation:
<span>Density is entirely unrelated to an object's size. It is a property of a given</span>
Voltmeter is used to find the potential difference between two points.
We always connect it in parallel to the points where we need the potential difference.
Here in order to make the reading accurate we can increase the resistance of voltmeter so that it can not withdraw any current from the circuit.
Clever problem.
We know that the beat frequency is the DIFFERENCE between the frequencies of the two tuning forks. So if Fork-A is 256 Hz and the beat is 6 Hz, then Fork-B has to be EITHER 250 Hz OR 262 Hz. But which one is it ?
Well, loading Fork-B with wax increases its mass and makes it vibrate SLOWER, and when that happens, the beat drops to 5 Hz. That means that when Fork-B slowed down, its frequency got CLOSER to the frequency of Fork-A ... their DIFFERENCE dropped from 6 Hz to 5 Hz.
If slowing down Fork-B pushed it CLOSER to the frequency of Fork-A, then its natural frequency must be ABOVE Fork-A.
The natural frequency of Fork-B, after it gets cleaned up and returns to its normal condition, is 262 Hz. While it was loaded with wax, it was 261 Hz.
