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3 years ago

7

Plz help with both questions (no link plz) 15 point and will make brainly

1 answer:

Nataliya [291]3 years ago

7 0

Answer:

question 5) 340.5

Step-by-step explanation:

abigails decorating buissness charge for every hour = $100+$13.50= 113.5

for 3 hour charges will be= 113.5 x 3= 340.5

hope it helps ❤️

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The sequence consisting of all natural numbers from 25 to 999 is given as follows.

timama [110]

Answer:

26 28 and 30

Step-by-step explanation:

we already have the first two as 26 and 28

third = a+5d

= 25+5

=30

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3 years ago

explain the transformation needed to convert the following data to a linear data set {(1, 0.98), (2, 1.39), (3, 1.71), (4, 1.98)

xz_007 [3.2K]

The given numbers are a set of points. To convert this into a linear data set, you can do data fitting. The easiest way to do this is using a software. In this case, I used MS Excel. You plot the points and set a linear trendline. The linear equation for this set of data is: y = 0.286x + 0.784

You can refer to the image to further understand the procedure.

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3 years ago

Becker catches a fish that's 3/12 of a yard long. to keep the fish, it has to be longer than 1/3 of a yard. can Becker his fish?

Ann [662]

No
Just simply give each fraction a common denominator. In this case I will use 12. So just multiply both sides of 1/3 by 4 to get 4/12. Since 4/12 is greater than 1/3, he cannot keep the fish

5 0

3 years ago

What is the solution of the proportion?

Dennis_Churaev [7]

D/48=14/12

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5 0

3 years ago

Read 2 more answers

Identify the scale factor used to graph the image below

Vlad [161]

Answer:

$Scale = \frac{2}{3}$

Step-by-step explanation:

To solve this question, I'll use the coordinates of SV and S'V' as points of reference.

From the attachment:

$S = (3,6)$

$V = (15,3)$

$S' = (2,4)$

$V' = (10,2)$

First, calculate distance SV

Distance formula is:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

For SV:

$d_1 = \sqrt{(15 - 3)^2 + (3 - 6)^2}$

$d_1 = \sqrt{(12)^2 + (-3)^2}$

$d_1 = \sqrt{144 + 9}$

$d_1 = \sqrt{153}$

For S'V'

$d_2 = \sqrt{(10 - 2)^2 + (2 - 4)^2}$

$d_2 = \sqrt{64 + 4}$

$d_2 = \sqrt{68}$

The scale factor is then calculated using:

$Scale = \frac{S'V'}{SV}$

$Scale = \frac{d_2}{d_1}$

Substitute values of d1 and d2

$Scale = \frac{\sqrt{68}}{\sqrt{153}}$

$Scale = \sqrt{\frac{68}{153}}$

$Scale = \sqrt{\frac{1}{2.25}}$

$Scale = \frac{1}{1.5}$

Express as a proper fraction

$Scale = \frac{1*2}{1.5*2}$

$Scale = \frac{2}{3}$

7 0

3 years ago