Answer:
A.The data should be treated as paired samples. Each pair consists of an hour in which the productivity of the two workers is compared.
Explanation:
If the mean productivity of two workers is the same.
For a random selection of 30 hours in the past month, the manager compares the number of items produced by each worker in that hour.
There are two samples and the productivity of the two men is paired for each hour.
Answer:
8*8=64
Step-by-step explanation:
Don't worry! Keep on trying! I hope this helps! Have a great rest of your day!
Hi there,
This is the original inequality equation:

So, we first need to find the critical points of equality, and we can do that by switching the less than sign to an equal sign.

Now, we multiply both sides by x + 1:

Then, we multiply both sides by x - 1:

Next, we subtract x² from both sides:

After that, we solve for x. We do this by adding -x to both sides and dividing by 2. Doing so gives us x = 0, which is our first critical point. We need to find a few more critical points by testing x = -1 and x = 1. Here is how we do that:
<span>x = <span>−1 </span></span>(Makes left denominator equal to 0)<span>x = 1 </span>(Makes right denominator equal to 0)Check intervals in between critical points. (Test values in the intervals to see if they work.)<span>x <<span>−1 </span></span>(Doesn't work in original inequality)<span><span><span>−1 </span>< x </span><0 </span>(Works in original inequality)<span><span>0 < x </span>< 1 </span>(Doesn't work in original inequality)<span>x > 1 </span><span>(Works in original inequality)
Therefore, the answer to your query is
-1 < x < 0 or x > 1. Hope this helps and have a phenomenal day!</span>
In case it is lost, it will not be able to be cashed except to be deposited into your account.
For a function, if it has an inverse function, keep in mind that, the "domain of the original, is the range of the inverse, and the range of the original, is the domain of the inverse", what the dickens does that mean?
well, it means the values for "x" and f(x), on the inverse, are the same values, but swapped up, therefore