The product of −3 1/4 and −1 1/2 as a mixed number is 
.
The product of −3 1/4 and −1 1/2 as a simplified form is 
<h3>What is products and mixed numbers?</h3>
Thew products between two terms can be described as the multiplication operation of the the two terms to give a term which is been performed by the use of the operation sign (*) between the two terms.
The mixed number can be defined as the numbers that contains whole numbers as well as the denominators and numerator.
It should be noted that the product of −3 1/4 and −1 1/2 can be done as (
Read more on mixed number here: brainly.com/question/21610929
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Answer:
Pam: $181
Amanda: $362
Julie: $452
Step-by-step explanation:
(What does Mike have to do with this problem?)
Let a = Amanda's pay
Let p = Pam's pay
Let j = Julie's pay
"Amanda made twice what Pam earned"
a = 2p
"Julie made $90 more than Amanda"
j = a + 90
j = 2p + 90
Pam earned p
Total salary
a + p + j = 2p + p + 2p + 90
Total salary
$995
2p + p + 2p + 90 = 995
5p = 905
p = 181
a = 2p = 2(181) = 362
j = 2p + 90 = 362 + 90 = 452
Answer:
Pam: $181
Amanda: $362
Julie: $452
Answer:
The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
Step-by-step explanation:
Let be 
, where 
is the stopping distance measured in metres and 
is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.
The procedure to find the speed related to the given stopping distance is described below:
1) Construct the graph of 
.
2) Add the function 
.
3) The point of intersection between both curves contains the speed related to given stopping distance.
In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
Answer:
2 hours
Step-by-step explanation:
add the time before and after adding 30 mins. (1 hour and 45 minutes/ 2 hours and 15 mins.) then divide by 2
<em> would say that the answer is </em><em>A. 25 cm</em><em> only because 37-12=25 and I don't necessarily know what the question is trying to ask.</em>
<em>Hope this Helps!<3</em>
