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Andrews [41]
3 years ago
15

How do I solve these problems I'm trying to find the cheapest deal

Mathematics
2 answers:
atroni [7]3 years ago
7 0
2.79 / 2 = 1.395 rounds to 1.40 per roll
8.99 / 6 = 1.498 rounds to 1.50 per roll

the better deal (cheapest) is the 2 roll package

** if u want price per roll (price / roll) ...u divide the price by the number of rolls
ozzi3 years ago
3 0
Take the total price and divide by the number of rolls that will tell you the price per roll
You might be interested in
A box with no top is to be constructed from a piece of cardboard whose length measures 12 inches more than its width. The box is
MAXImum [283]

Answer:

Width is 12 inches and height is 4 inches.

Step-by-step explanation:

Let the width of the piece of cardboard be = w inches

Then length is = w+12 inches

As given, 4 inch squares are cut from each corner;

So, the width is = w-8 inches

Length is = w+12-8=w+4 inches

When we are folding the cut portion, that gives the height as = 4 inches

The volume is given by : length x width x height

And volume is given as 256 cubic inches

So, 256=(w+4)(w-8)(4)

=> 256=(w^{2}-4w-32)4

=> 64=(w^{2}-4w-32)

=> w^{2} -4w=96

or w^{2} -4w-96=0

=> w^{2} -12w+8w-96=0

=> w(w-12)+8(w-12)=0

We get , (w+8)=0 ; w = -8(neglect the negative value)

(w-12)=0 ; w = 12 inches

And length = 12+12=24 inches

Hence, dimensions are : L = 24 inches ; w = 12 inches and h = 4 inches

We can check by putting these values in equation : 256=(w+4)(w-8)(4)

256=(12+4)(12-8)(4)

=> 256=(16)(4)(4)

=> 256=256

5 0
3 years ago
Tanisha cut a triangle with angles of 62°, 30°, and 88° in three pieces so that each piece had one angle of the triangle. She ar
-Dominant- [34]
The right answer for the question that is being asked and shown above is that: "180 - line." Tanisha cut a triangle with angles of 62°, 30°, and 88° in three pieces so that each piece had one angle of the triangle.She arranged the three angles <span>connected together such that the three corners of the triangle were all touching.</span><span> </span>
8 0
3 years ago
9.1(6)+8.7(7)=_+60.9<br> How do I solve this?
timurjin [86]

Answer:

The answer is <u>54.6</u>.

9.1(6)+8.7(7)=<u>54.6</u>+60.9

Step-by-step explanation:

Given:

9.1(6)+8.7(7)=_+60.9

Now, to solve it:

9.1(6)+8.7(7)=_+60.9

Let the _be x.

So, we remove parenthesis first that makes it multiply with the number next to it:

9.1\times 6+8.7\times 7=x+60.9

54.6+60.9=x+60.9

Now adding on L.H.S:

115.5=x+60.9

Subtracting on both sides by 60.9 we get:

54.6=x

x=54.6

Therefore, the answer is 54.6.

7 0
3 years ago
[4]
Tanya [424]

Answer:

Angle ACD = 38°

Step-by-step explanation:

The full, correct question is presented the attached image to this solution.

Given

Point O is the centre if the circle

Points A, B, C and D are points on the circle

Angle AOB = 140°

Angle OAC = 14°

Angle AOB = 2 × (Angle ACB) [angle subtended at the centre of the circle is twice the angle subtended at the circumference of the circle)

140° = 2 × (Angle ACB)

Angle ACB = (140°/2) = 70°

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180° [sun of angles in a triangle is 180°]

But Angle OAB = Angle ABO = a [base angles of an iscosceles triangle are equal since OA and OB are both radii for the circle O)

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180°

140° + a + a = 180°

2a = 40°

a = (40/2) = 20°

Angle OAB = Angle ABO = 20°

Angle CAB = (Angle OAC) + (Angle OAB) = 14° + 20° = 34°

Triangle ADC is an iscosceles triangle, hence,

Angle DAC = Angle ACD = x [base angles of an iscosceles triangle are equal]

But

(Angle DCB) + (Angle DAB) = 180° [Opposite angles of a cyclic quadilateral (a quadilateral inscribed in a circle) sum up to give 180°]

Angle DCB = (Angle DCA) + (Angle ACB) = (x + 70°)

Angle DAB = (Angle DAC) + (Angle CAB) = (x + 34°)

(Angle DCB) + (Angle DAB) = 180°

(x + 70°) + (x + 34°) = 180°

2x + 104° = 180°

2x = 180° - 104° = 76°

x = (76°/2) = 38°

Angle DAC = Angle ACD = 38°

Angle ACD = 38°

Hope this Helps!!!

7 0
3 years ago
Resuelve las siguientes ecuaciones: -x^2 - x =0 -X^2 + 12x = 0 3X^2 - 9x = 0 X^2 - 2x - 3 = 0
vaieri [72.5K]

Responder:

<em>a) 1 </em>

<em>b) 12 </em>

<em>c) 3 </em>

<em>d) -1 y 3 </em>

Explicación paso a paso:

Dadas las siguientes ecuaciones;

a) x²-x =0

x² = 0+x

x² = x

x = 1

b) -x²+12x = 0

-x² = -12x

x² = 12x

x = 12

c) 3x² - 9x = 0

Suma 9x a ambos lados

3x²-9x+9x = 0+9x

3x² = 9x

3x = 9

x = 9/3

x = 3

d) x²-2x-3 = 0

x²-3x+x-3 = 0

x(x-3)+1(x-3) = 0

(x+1)(x-3) = 0

x+1 = 0 y x-3 = 0

x = -1 y 3

4 0
2 years ago
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