Cecelia says she can use addition to solve multiplication problems. Is Cecelia correct? Explain

2 answers:

8 0

Yes, you can use addition to solve multiplication problems!

Here are some examples:

-Let's use 5 x 2 for example. 5 x 2= 10 can be solved as 5 + 5 = 10 since you are technically adding 5 twice.
-Another example would be 3 times 5. 3 x 5 = 15 can be solved by 3 + 3 + 3 +3 + 3 = 15 which is adding 3 five times.
-10 times 10 = 100 : 10 + 10 + 10 + 10 + 10 + 10+ 10 + 10 + 10 +10 = 100

Hope these examples help! :)

blsea [12.9K]3 years ago

6 0

Yes. because she can just add how many times she need to multiply. For example let's say she wants to multiply 7 times 7. You can add 7+7+7+7+7+7+7

You might be interested in

I need help with algebra function notation

lutik1710 [3]

What is the question

5 0

3 years ago

4 over 5 in standard form

postnew [5]

Answer:0.8

Step-by-step explanation:

it is basically 10 times 8 to the power of -1

7 0

3 years ago

Given circle X with radius 10 units and chord AB with length 12 units, what is the length of segment CX, which bisects the chord

andrew-mc [135]

Consider the circle with center X, as shown in the figure.

Draw the diameter of the circle which is parallel to cherd AB, as shown in the figure.

Since the diameter and AB are parallel, then the line segment XC which bisects AB at C, will be perpendicular to AB.

SO triangle XCB is a right triangle. Thus the length of CX, by the Pythagorean theorem is

$\sqrt{ XB^{2}- CB^{2}} = \sqrt{ 10^{2}- CB^{6}}= \sqrt{100-36}= \sqrt{64}=8$ units.

Answer: 8 units

7 0

3 years ago

an electrician needs to cut a 49 m piece of wire into two pieces so that one piece is 5 m longer than the other piece. What is t

kumpel [21]

8 would be the length of each piece of wire I think.

7 0

3 years ago

Read 2 more answers

What is the largest perimeter possible for a rectangle with positive whole number dimensions and an area of 40 cm?

Vladimir79 [104]

Answer:

C, 82 cm

Step-by-step explanation:

If the area of a rectangle is it's length times it's width and for the problem, it's maximum area must be 40cm than 40x1 would offer the largest perimeter with the smallest area respectively totalling at 82 cm.

8 0

3 years ago