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lara31 [8.8K]
3 years ago
15

2. If it takes Ashley 3 seconds to run from the batter’s box to first base at an average speed of 6.5 meters per second, what is

the distance she covers in that time?
Physics
2 answers:
Semmy [17]3 years ago
8 0
6.5 meters per second mutiplied by 3 seconds and you get 19.5 meters
11111nata11111 [884]3 years ago
4 0

3 x 6.5 ... easy = 19.5m
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3 years ago
The microwaves in a certain microwave oven have a wavelength of 12.2 cm. How wide must this oven be so that it will contain five
leva [86]

Answer:

a

 l = 0.305 \  m

b

  f = 3.0*10^{11} \  Hz

Explanation:

From the question we are told that

  The  wavelength is  \lambda  =  12.2 \  cm  = 0.122 \  m

  The  number of antinodal planes of the electric field considered is n  =  5

The  width is mathematically represented as

       l  =  \frac{ n \lambda}{2}

       l = \frac{5 * 0.122 }{ 2}

      l = 0.305 \  m

Generally the  frequency the errors was made is  mathematically represented as

   f =  \frac{c}{\lamda_k}

Here c is the speed of light with value  c =  3.0*10^{8} \  m/s

     \lambda_k is the wavelength of the microwave has to be in order for there still to be five antinodal planes of the electric field along the width of the oven, which is mathematically represented as

     \lambda_k  =  \frac{ \lambda *  \frac{0.04}{2} }{n/2}

      \lambda_k  =  \frac{0.122*0.02}{5/2}

So

   f =  \frac{3.0*10^{8}}{0.000976}

    f = 3.0*10^{11} \  Hz

   

       

8 0
3 years ago
A diver running 2.5 m/s dives out horizontally from the edge of a vertical cliff and 3.0 s later reaches the water below. how hi
Elodia [21]

<u>Answer:</u>

a) Height of cliff = 44.145 meter

b) 7.5 meter far from its base the diver hit the water.

<u>Explanation:</u>

 We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Diver's vertical motion:

   Initial velocity = 0 m/s, acceleration = 9.8 m/s^2, we need to calculate displacement when time is 3 seconds.

  s= ut+\frac{1}{2} at^2\\ \\ =0*3+\frac{1}{2} *9.81*3^2\\ \\ =44.145meter

 So height of cliff = 44.145 meter.

b) Diver's horizontal motion:

Initial velocity = 2.5 m/s, acceleration = 0 m/s^2, we need to calculate displacement when time is 3 seconds.

s= 2.5*3+\frac{1}{2}*0*3^2\\ \\ =7.5meter

So 7.5 meter far from its base the diver hit the water.

5 0
3 years ago
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