Answer:
The ranking of the stars are 5 → 2 → 4 → 3 → 1
Explanation:
To solve the question, we note that an approaching star has a blue-shift, a regressing star has a red-shift and a crossing star will have no shift.
The magnitude of the blue-shift or red-shift is dependent on the speed of the stars.
Therefore we have the rank of the stars based on the Doppler shift that would be detected on earth from largest blue-shift to largest red-shift given as
5 → 2 → 4 → 3 → 1.
2 weeks ago, oh boy.
So we know k is 10 N/m and it is stretch 0.1m.
For the conservation of energy, we know the mechanical energy in the system is constant, and we know the energy switches from potential elastic energy to kinetic energy. So we can solve for the maximum potential elastic energy, which should tell us the mechanical energy.
Since we are told it is stretch 0.1m and we are given the spring constant, we can solve for max potential elastic energy.
Mechanical energy = Max potential = 0.5kA^2
This gives us 0.5(10N/m)(0.1m)^2 = 0.05J
The maximum kinetic energy is when the potential elastic energy is zero, thus 0.05J would be the maximum kinetic energy.
Hope this helps!
Answer:
<u>b. 2.27 N</u>
Explanation:
Fe = (k)(Q1)(Q2) / d²
k ≈ 9 × 10⁹ N m² / C² [Coulomb's Constant] or 8.98 × 10⁹ (nearest hundredth).
q = particle charge [Coulombs; C]
d = distance [Meters; m]
Fe = Electrostatic force [Newtons; N]
________________________________
Fe = (9×10⁹)(3.5 × 10^(-8)(-4.5 × 10^(-6))/(.25)² N =
(9)(3.5)(-4.5) × (10^(9))(10^(-8))(10^(-6) / (.25)² N =
(9)(3.5)(-4.5) × (10^(9 - 8 - 6)) / (.25)² N =
(-141.75) × 10^(-5) / (.0625) N =
141.75 × 10^(-5) / (.0625) N
[opposite direction] =
(1.4175 × 10^(2)) × 10^(-5) / (.0625) N
[opposite direction] =
1.4175 × 10^(-3) / .0625 N
[opposite direction] =
1.4175 × 10^(-3) / 6.25 × 10^(-2) N =
14.175 / 6.25 N [opposite direction] =
2.268 N ≈ 2.27 N [opposite direction].
