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olga2289 [7]
3 years ago
12

Which pair of ions is most likely to form an ionic bond? A. H- and H- B. Mg2+ and Br- C. N3- and O2- D. Na+ and Al3+

Physics
2 answers:
Georgia [21]3 years ago
6 0
\textsf{answer is b .}\\\textsf{because magnesium is very hungry}\\\textsf{so mg  takes 2electrons}
Setler [38]3 years ago
3 0

<u>Answer:</u> The pair of ions that is most likely to form an ionic bond is Mg^{2+}\text{ and }Br^-

<u>Explanation:</u>

Ionic compound is defined as the compound which is formed by complete transfer of electrons from one atom to another atom.

The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal (carrying positive charge) and a non-metal (carrying negative charge)

Ionic compound is formed by the attraction of oppositely charged ions.

For the given options:

Magnesium ion (Mg^{2+}) and bromine ion (Br^-) will attract each other because they are oppositely charged and will lead to form ionic compound.

The ionic compound formed is magnesium bromide (MgBr_2)

Hence, the pair of ions that is most likely to form an ionic bond is Mg^{2+}\text{ and }Br^-

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A swimmer bounces straight up from a diving board and falls feet first into a pool. She starts with a velocity of 4.00 m/s, and
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Answer:

(a) t = 1.14 s

(b) h = 0.82 m

(c) vf = 7.17 m/s

Explanation:

(b)

Considering the upward motion, we apply the third equation of motion:

2gh = v_f^2 - v_i^2

where,

g = - 9.8 m/s² (-ve sign for upward motion)

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vf = final speed = 0 m/s

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Therefore,

(2)(9.8\ m/s^2)h = (0\ m/s)^2-(4\ m/s)^2\\

<u>h = 0.82 m</u>

Now, for the time in air during upward motion we use first equation of motion:

v_f = v_i + gt_1\\0\ m/s = 4\ m/s + (-9.8\ m/s^2)t_1\\t_1 = 0.41\ s

(c)

Now we will consider the downward motion and use the third equation of motion:

2gh = v_f^2-v_i^2

where,

h = total height = 0.82 m + 1.8 m = 2.62 m

vi = initial speed = 0 m/s

g = 9.8 m/s²

vf = final speed = ?

Therefore,

2(9.8\ m/s^2)(2.62\ m) = v_f^2 - (0\ m/s)^2\\

<u>vf = 7.17 m/s</u>

Now, for the time in air during downward motion we use the first equation of motion:

v_f = v_i + gt_1\\7.17\ m/s = 0\ m/s + (9.8\ m/s^2)t_2\\t_2 = 0.73\ s

(a)

Total Time of Flight = t = t₁ + t₂

t = 0.41 s + 0.73 s

<u>t = 1.14 s</u>

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