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3 years ago

1. How much force would you have to apply to a 15kg object in order to accelerate it! a 2 m/s?

Physics

1 answer:

mihalych1998 [28]3 years ago

3 0

30N

Explanation:

Given parameters:

Mass of object = 15kg

Acceleration = 2m/s

Unknown:

Force = ?

Solution:

Force is given as the product of mass and acceleration:

F = m x a

m is the mass

a is the acceleration

Inputting the parameters:

F = 15 x 2 = 30N

The unit of force is newtons, N .

Learn more:

Force brainly.com/question/10470406

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A person is pushing a box. The net external force on the 60-kg box is stated to be 90 N. If the force of friction opposing the m

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Answer:

$b.1.5m/s^2$

Explanation:

We are given that

Mass of box=60kg

Net external force applied on the box=90 N

Friction force =30N

We have to find the acceleration of the box.

We know that

Net external force=ma

Substitute the values then we get

$90=60a$

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Hence, option b is true.

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Three people pull simultaneously on a stubborn donkey. Jack pulls eastward with a force of 64.7 N, Jill pulls with 61.5 N in the

USPshnik [31]

Answer:

F = 241.8 N θ = -18.7

Explanation:

To find the net force, we use Newton's second law, for this we decompose the force using trigonomer

Force 2

F2 = 61.5 N

cos 45 = F₂ₓ / F2 F₂ₓ = F2 cos 45

sin 45 = F₂_y / F2 F₂_y = F2 sin 45

force 3

F3 = 171 N

cos 45 = F₃ₓ / F3

sin 45 = F₃_y / F3

the total force can be found with its components

axis x direction (East-West)

Fₓ = 64.7 +61.5 cos 45 + 171 cos 45

Fₓ = 229.1 N

Y axis (direction North -Sur)

F_y = 61.5 sin 45 - 171 sin 45

F_y = - 77,428 N

the resulting force is

F = Fx i ^ + Fy j ^

F = (229.1 i⁻ 77,428 j⁾ N

we can use the Pythagorean theorem to find the module

F = √ (229.1 2 + 77,428 2)

F = 241.8 N

let's use trigonometry to find the direction

tan θ = F_y / Fₓ

θ = tan⁻¹ (F_y / Fₓ)

θ = tan⁻¹ (-77,428 / 229.1)

θ = -18.7

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