<span> Using conservation of energy
Potential Energy (Before) = Kinetic Energy (After)
mgh = 0.5mv^2
divide both sides by m
gh = 0.5v^2
h = (0.5V^2)/g
h = (0.5*2.2^2)/9.81
h = 0.25m
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Answer:
2800000J
Explanation:
Parameters given:
Mass = 920kg, weight = 920 * 9.8 = 9016N
Distance = 310m
Angle of inclination = 6.5°
Work done is given as :
W = F*d*cosA
Where A = angle of inclination
W = (9016 * 310 * cos6.5)
W = 2776993.59J
In 2 significant figures, W = 2800000J
You'd use the equation kinetic energy=mass*0.5*speed^2
So you'd rearrange this to get mass =kinetic energy /0.5 *speed^2
Which is mass= 1500J/0.5*35^2
=2.44897959183673469........kg
19685 mph to stay in orbit or 8 kilometers per second to stay in orbit if this dose not help tell me
Answer:
Explanation:
r(t) = A(cos wt i + sin wt f)
= A cos wt i + A sin wt j
x = A cos wt
y = A sin wt
radius r
r² = x² + y² ( This is equation of a circle with radius r )
= A² cos² wt +A² sin² wt
= A²
r = A
radius r = A
b )
speed = dr/dt
v = - Aw sinwt i + Aw coswt j
magnitude of velocity
I v I= Aw √(sin²wt + cos²wt)
= Aw ( constant )
acceleration
= dv / dt = - Aw² cos wt - Aw² sinwt
magnitude of acceleration
I a I = Aw²
= r w²
d ) centripetal force = m acceleration
m w² A
=
