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Step2247 [10]
2 years ago
10

Given the following geometric sequence, find the 12th term: {2, -4, 8, ...}.

Mathematics
1 answer:
jolli1 [7]2 years ago
5 0

A geometric sequence has a common ratio.

The formula for the nth term is

\sf{a_n =ar^{n-1} }

where,

  • an = nth term of the sequence,
  • a = first term of the sequence and
  • r = common ratio

<u>Given</u> -

  • A geometric sequence 2, -4, 8, ...

<u>To find</u> -

  • the 12th term of the given geometric sequence

<u>Solution</u> -

A.T.Q, a = 2 and r = -2

\rightarrow\sf{a_{12} =2(-2)^{12-1} }

\rightarrow\sf{a_{12 }=2(-2)^{11} }

\rightarrow\sf{a_{12} =2×(-2048) }

\rightarrow\bf{a_{12 }=-4096 }

<u>Hence, the 12th term is -4096</u>.

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Answer: 8

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An object is heated to 100°. It is left to cool in a room that
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Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

T₀ is the initial temp

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If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

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t = 5

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Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

50=70e^{5k} Divide both sides by 70 to get

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ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

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Divide both sides by 5 to get that

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T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

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t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

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