8×5=40
40h-3=0
+3
40h=3
÷40
h=3/40
F(x) basically just substitutes the "y"
so you would bring everything over to one side
y + 3 = 0
subtract 3
y = -3
then
f(x) = -3
That is B)
Both of the fractions can be added since they both have 8 as the denominator 3/8+5/8=8/8 which is a whole.
Y=-1/3x+2
Use photomath app
9514 1404 393
Answer:
- Angle 1 = 139°
- Angle 2 = 41°
- x = 29; exterior angle = 131°
Step-by-step explanation:
These problems let you make use of the fact that the sum of the remote interior angles is equal to the exterior angle.
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1. 53° +86° = ∠1
139° = ∠1
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2. ∠2 +92° = 133°
∠2 = 133° -92°
∠2 = 41°
__
3. (x +9)° +93° = (4x+15)°
87 = 3x . . . . . . . . . . . . . . . . subtract x+15°
29 = x . . . . . . . divide by 3
The exterior angle is ...
(4x +15)° = (4·29 +15)° = 131° . . . exterior angle