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tangare [24]
3 years ago
15

Solve the linear equation. 8x+32=2(25x−15)−11x8x+32=2(25x−15)−11x

Mathematics
1 answer:
Bogdan [553]3 years ago
8 0
It seems like you put the same equation up there twice, but no worries! :)

8x + 32 = 2(25x - 15) - 11x

Simplify.

8x + 32 = 50x - 30 - 11x

Add like terms.

8x + 32 = (50x - 11x) - 30

Simplify.

8x + 32 = 39x - 30

Now we must subtract 32 from both sides.

8x = 39x - 30 - 32

Then, subtract 39x from both sides.

8x - 39x = -30 - 32

Simplify.

-31x = -62

Finally, divide both sides by -31.

-31x ÷ -31 = -62 ÷ -31

Simplify.

x = 2

~Hope I helped!~

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y=3x-4

Step-by-step explanation:

Hi there!

Slope-intercept form: y=mx+b where <em>m</em> is the slope and <em>b</em> is the y-intercept (the value of y when x=0)

<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>

m=\displaystyle\frac{y_2-y_1}{x_2-x_1} where two points that fall on the line are (x_1,y_1) and (x_2,y_2)

On the graph, two points are highlighted for us: (0,-4) and (2,2). Plug these into the formula:

m=\displaystyle\frac{2-(-4)}{2-0}\\\\m=\displaystyle\frac{2+4}{2}\\\\m=\displaystyle\frac{6}{2}\\\\m=3

Therefore, the slope of the line is 3. Plug this into y=mx+b:

y=3x+b

<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>

y=3x+b

Recall that the y-intercept occurs when x=0. Given the point (0,-4), the y-intercept is therefore -4. Plug this into y=3x+b:

y=3x+(-4)\\y=3x-4

I hope this helps!

5 0
2 years ago
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