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nalin [4]
3 years ago
14

In the first two hours of the trip, Julissa drove 120 miles. In the nest hour, she traveled only 48 miles. What was Julissa's av

erage speed in miles per hour (mph) for the 3 hour drive?
Mathematics
2 answers:
Zigmanuir [339]3 years ago
8 0
Average speed=(total distance traveled)/(total time of travel)

average speed=(120+48)/3

average speed=56 mph
Digiron [165]3 years ago
4 0
The first two hours was 60 miles an hour and after that it was only 48 miles an hour. She drove 168 miles altogether in 3 hours. The final answer is 56 MPH on average for all 3 hours. 168/3= 56 MPH
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What’s the answer and how do I solve it?
Dimas [21]

Answer:

x= -1, x=3

Step-by-step explanation:

The “zeros” of a quadratic function are where the parabola intersects the x axis. In that graph the parabola touches x=-1 and x=-3. Therefore that is the answer.

8 0
2 years ago
A piece of property lies between two parallel streets as shown. m<1=(2x+6)°,and m<2=(3x+9)°. What is the relationship betw
kolezko [41]
  • The angles are supplementary angles
  • The measure of angle m<1 and m<2 are 72 and 108 degrees respectively

Find the diagram attached. From the figure, the sum of the angles m<1 and m<2 are supplementary

Given the following angles

m<1 = 2x + 6

m<2 = 3x + 9

Since both angles are supplementary, hence;

2x + 6 + 3x + 9 = 180

5x + 15 = 180

5x = 180 - 15

5x = 165

x = 165/5

x = 33

Get the measure of m<1;

m<1 = 2x + 6

m<1 = 2(33) + 6

m<1 = 66 + 6

m<1 = 72degrees

Get the measure of m<2:

m<2 = 180 - m<1

m<2 = 180 - 72

m<2 = 108degrees

Hence the measure of angle m<1 and m<2 are 72 and 108 degrees respectively

Learn more here: brainly.com/question/22309882

5 0
2 years ago
Suppose T is a transformation from ℝ2 to ℝ2. Find the matrix A that induces T if T is reflection over the line y=1/2x
trapecia [35]

Answer:

A = \left[\begin{array}{cc}1&\frac{4}{5}\\\frac{4}{3}&-\frac{3}{5}\end{array}\right]

Step-by-step explanation:

We have to see how the canonical vectors are transformed throught T. Lets first define T in any basis.

Since T is a reflection, then any element of the line y = x/2 if fixed by T. Therefore T(2,1) = (2,1).

On the other hand, any vector perpendicular to the line direction should be sent to its opposite value. We can take, for example, (-1,2) (note that the scalar product (2,1) * (-1,2) = -2+2 = 0). As a consecuence T(-1,2) = (1,-2). We have

  • T(2,1) = (2,1)
  • T(-1,2) = (1,-2)

By summing the first vector with the double of the second one we get, using linearity

T(0,5) = T( (2,1) + 2(-1,2)) = T(2,1) + 2T(-1,2) = (2,1) + 2(1,-2) = (4,-3)

Hence, T(0,1) = (4/5,-3/5)

Now, we take the second vector and substract it the double of the first one (to kill the second variable)

T(-3,0) = T( (-1,2) - 2*(2,1) ) = T(-1,2) -2T(2,1) = (1,-2)-2(2,1) = (-3,-4)

Therefore, T(1,0) = (1,4/3)

The matrix A induced by  T has in its first column T(1,0) and in its second column T(0,1). We conclude that

A = \left[\begin{array}{cc}1&\frac{4}{5}\\\frac{4}{3}&-\frac{3}{5}\end{array}\right]

3 0
3 years ago
Roberto deposited $5,000 into an account with 4.2% interest, compounded monthly.
Marina86 [1]

Answer:

$50,581.9

Step-by-step explanation:

8 0
3 years ago
A triangle has height 15 in. And area 120 in2. what is length of its base
Novosadov [1.4K]
Working out is in picture

4 0
2 years ago
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