The cost of each bag of soil is $ 16.25 and the cost of each bag of fertilizer is $ 12.99.
<h3>What is the linear system?</h3>
A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.
Mr. Ellis has started a vegetable garden.
He bought 15 bags of soil and 3 bags of fertilizer for 282.72.
He realized he did not have enough supplies so he bought another 5 bags of soil and 2 bags of fertilizer for 107.23.
Let the cost of each bag of soil be x and the cost of a bag of fertilizer be y.
Then we have the linear equations,
15x + 3y = 282.72
5x + 2y = 107.23
On solving the equations 1 and 2, we have
x = 16.25 and y = 12.99
The cost of each bag of soil is $ 16.25 and the cost of each bag of fertilizer is $ 12.99.
More about the linear system link is given below.
brainly.com/question/20379472
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Answer:
Think it's 109.33
Step-by-step explanation:
look it up brodie
To solve this, we have to find the volume of the cylinder first. The formula to be used is

Given:V= ?r= 6cmh= 10cm
Solution:

V= (3.14)(6cm)

x 10cmV= (3.14)(

) x 10cmV= (

) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is. Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.
Answer: The nth term of a geometric progression is Tn = ar^(n-1)
A. 12
B. 3.6
C. -3/4
D. 0.6
Step-by-step explanation:
The nth term of a geometric progression is Tn = ar^(n-1)
Where Tn= nth term
a = first term
r = common ratio
n = number
A. a6 = (2*6) = 12
B. a6 = (0.6*6) = 3.6
C. a6 = (-1/8*6) = -3/4
D. a6 = (0.1*6) = 0.6
You do (50+12)+11 to get Tim's height.
Mike Plus Taller
Which is... 73 cm!!
Easy, right? Except that it is like 2 ft tall...