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posledela
3 years ago
13

Simplify $\dfrac{1}{\sqrt2+1}+\dfrac{1}{\sqrt2-1}.$

1%7D%2B%5Cdfrac%7B1%7D%7B%5Csqrt2-1%7D.%24" id="TexFormula1" title="Simplify $\dfrac{1}{\sqrt2+1}+\dfrac{1}{\sqrt2-1}.$" alt="Simplify $\dfrac{1}{\sqrt2+1}+\dfrac{1}{\sqrt2-1}.$" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
bulgar [2K]3 years ago
6 0

Answer:

Step-by-step explanation:

common denominator

(\sqrt(2)+1)(\sqrt(2)-1) = (\sqrt{2})^2-1^{2}=2-1 = 1

Add with common denominator

\dfrac{1}{\sqrt2+1}+\dfrac{1}{\sqrt2-1}.

= \frac{{\sqrt2-1}}{1} + \frac{\sqrt2+1}{1}

=2* (\sqrt2)

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3 years ago
1. What is the slope of a line parallel to -8x + y = 2?
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Step-by-step explanation:

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