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3 years ago

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The Punic Wars began in 264 B.C. and ended in 146 B.C. How long did the Punic Wars last??

2 answers:

pishuonlain [190]3 years ago

4 0

Answer:

The first two wars were long—23 years and 17 years, separated by an interval of 23 years. The third war lasted nearly three years. It started 52 years after the end of the second war. All three wars were won by Rome, which subsequently emerged as the greatest military power in the Mediterranean Sea.

Step-by-step explanation:

natka813 [3]3 years ago

3 0

Answer:

the answer is not in Mathemics because it's wrong answer

Step-by-step explanation:

can you take off that brainly and create new one plz

and get some brainlest!

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The Yates family’s cell phone bill is $175 a month. How much will they pay for a year (12 months)?

alexira [117]

Answer:

The Yates phone bill will be $2100 for a year.

Step-by-step explanation:

175x12=2100

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3 years ago

If the perimeter of a triangle is 31 ft and two of the side lengths are 15 ft and 10 ft, what is the length of the third side?

erastovalidia [21]

Answer:

C) 6 ft

Step-by-step explanation:

Perimeter is just adding the side lengths together so...

31-15-10=x

6=x

so your answer is 6ft

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3 years ago

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babymother [125]

Answer:

y = -5x +5

Step-by-step explanation:

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3 years ago

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Firdavs [7]

Answer:

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Step-by-step explanation:

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3 years ago

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What are the solutions of x² + 6x - 6 = 10?

Likurg_2 [28]

Answer: x=- 8 or x=2

Step-by-step explanation:

1. To solve this problem you can applly the quadratic formula, which is shown below:

$x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}$

2. The quadratic equation is:

$x^{2}+6x-6-10=0\\x^{2}+6x-16=0$

3. Then:

a=1

b=6

c=-16

4. Therefore, when you substitute these values into the quadratic formula, you obtain the following result:

$x=\frac{6+/-\sqrt{6^{2}-4(1)(-16)}}{2(1)}$

$x_1=-8\\x_2=2$

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3 years ago

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