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AlekseyPX
3 years ago
8

The Haber process can be used to produce ammonia (NH3) from hydrogen gas (H2) and nitrogen gas (N2). The balanced equation for t

his process is shown below.
3H2 + N2 mc025-1.jpg 2NH3

The molar mass of NH3 is 17.03 g/mol. The molar mass of H2 is 2.0158 g/mol. In a particular reaction, 0.575 g of NH3 forms. What is the mass, in grams, of H2 that must have reacted, to the correct number of significant figures?
0.1
0.102
0.10209
0.1021
Chemistry
2 answers:
neonofarm [45]3 years ago
7 0
.102 would be the correct number of significant figures
beks73 [17]3 years ago
5 0

Answer : The mass of H_2 in grams is 0.102g.

Solution : Given,

Molar mass of NH_3 = 17.03 g/mole

Molar mass of H_2 = 2.0158 g/mole

Given Mass of NH_3 = 0.575 g

First we have to calculate the moles of NH_3.

\text{ Moles of }NH_3=\frac{\text{ Given mass of }NH_3}{\text{ Molar mass of }NH_3} = \frac{0.575g}{17.03g/mole} = 0.0337 moles

The given balanced equation is,

3H_2(g)+N_2(g)\rightarrow 2NH_3(g)

From the above reaction, we conclude that

2 moles of NH_3 produced from 3 moles of H_2

then the 0.0337 moles of NH_3 produces to give \frac{3moles\times 0.0337moles}{2moles} moles of H_2

The moles of H_2 = 0.0505 moles

The mass of H_2 = Moles of H_2 × Molar mass of H_2 = 0.0505 moles × 2.0158 g/mole = 0.10179 g

The mass of H_2 in the correct number of significant figures is 0.102 g.

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