Given:
Diprotic weak acid H2A:
Ka1 = 3.2 x 10^-6
Ka2 = 6.1 x 10^-9.
Concentration = 0.0650 m
Balanced chemical equation:
H2A ===> 2H+ + A2-
0.0650 0 0
-x 2x x
------------------------------
0.065 - x 2x x
ka1 = 3.2 x 10^-6 = [2x]^2 * [x] / (0.065 - x)
solve for x and determine the concentration at equilibrium.
Answer:
1.75M
Explanation:
molarity = number of moles of solute/ number of L of solution =
=0.35 mol/0.2L = 1.75 mol/L = 1.75 M
Explanation:
At STP ,2.24 L contain 0.1 mole of N²
<h2>So,No. of molecules of N2 = 6.022*10²²</h2>
Answer: Velocity
Explanation:
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