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IgorLugansk [536]
3 years ago
14

Which of the following explains how Albert Einstein tried to influence the use of his discovery of the energy equation?

Chemistry
1 answer:
Jobisdone [24]3 years ago
7 0

Answer: D. He recommended applying the principles of nuclear fission to defend against enemies.

Which of the following explains how Albert Einstein tried to influence the use of his discovery of the energy equation?

A. He opposed the use of nuclear fusion during the Manhattan Project.

B. He recommended uncontrolled fusion for medical testing and treatment.

C. He supported the use of radioactive elements for medical diagnostic purposes.

<u><em>D. He recommended applying the principles of nuclear fission to defend against enemies.</em></u>

Explanation:

I just took the test and the correct answer is D. He recommended applying the principles of nuclear fission to defend against enemies!

Good Luck!!

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1 lb of CO2 occupies 0.6 ft^3 at a pressure of 200 psi. Determine the temperature of the system.
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<u>Answer:</u> The temperature of the system is 273 K

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  

Given mass of carbon dioxide = 1 lb = 453.6 g   (Conversion factor: 1 lb = 453.6 g)

Molar mass of carbon dioxide = 44 g/mol

Putting values in above equation, we get:

\text{Moles of carbon dioxide}=\frac{453.6g}{44g/mol}=10.31mol

To calculate the temperature of gas, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of carbon dioxide = 200 psia = 13.6 atm   (Conversion factor:  1 psia = 0.068 atm)

V = Volume of carbon dioxide = 0.6ft^3=16.992L    (Conversion factor:  1ft^3=28.32L )

n = number of moles of carbon dioxide = 10.31 mol

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the system = ?

Putting values in above equation, we get:

13.6atm\times 16.992L=10.31mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times T\\\\T=273K

Hence, the temperature of the system is 273 K

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