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andrew11 [14]
4 years ago
9

you can feel the heat waves from small electric heater on your hands and face even though the heater is on the other side of the

room this is an example of
Physics
1 answer:
enyata [817]4 years ago
3 0
Radiation
hope this helps
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An infinite long straight wire is uniformly charged, the charge density is a. Use Coulomb's law to calculate the electric field
bixtya [17]

Answer:

\vec{E} = \frac{a}{2\pi \epsilon_0 R}\^R

Explanation:

Since the wire is infinitely long, we will use Gauss' Law:

\int\vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}

We will draw an imaginary cylindrical surface with height h around the wire. The electric flux through the imaginary surface will be equal to the net charge inside the surface.

In that case, the net charge inside the imaginary surface will be the portion of wire with height h. Then the charge of that portion will be equal to

Q_{enc} = ah

The left-hand side of the Gauss' Law is the flux through the imaginary surface. Since we choose our surface as a cylinder, of which we know the area, we do not have to take the surface integral.

\int\vec{E}d\vec{a} = E2\pi R h

where R is the radius of the imaginary cylinder.

Finally, Gauss' Law gives

E2\pi Rh = \frac{ah}{\epsilon_0}\\E = \frac{a}{2\pi \epsilon_0 R}

The vector expression is

\vec{E} = \frac{a}{2\pi \epsilon_0 R}\^R

As you can see, the electric field is independent from the height h, since that is merely an imaginary cylinder to apply Gauss' Law. In the end, what matters is the charge density of the wire and the distance from the wire.

4 0
4 years ago
Which of the following statements describes an interaction between the atmosphere and biosphere?
Schach [20]

Answer:

well 1. its not 100 points it is 5 points.....and 2.the answer is D. I did the same test and it was D.

Explanation:

brainliest?

4 0
3 years ago
Gold has a density of 19.3 grams per cubic centimeter. what is the density of gold in metric tons per cubic meter?
valina [46]
In order to determine this, we will first need some conversions. We will need to convert metric tons and grams into one another and also cubic centimeters to cubic meters into one another.

1 metric ton = 1000 kg

1 kg = 1000 grams

1 metric ton = 10⁶ grams

So 10⁶ grams / metric ton


1 meter = 100 cm
1 m³ = (100)³ cm³
1 m³ = 10⁶ cm³

So 10⁶ cm⁶ / m³

Now, we manipulate the given value:

(19.3 grams / cm³) * (1 metric ton / 10⁶ grams) * (10⁶ cm³ / m³)
= 19.3 metric tons / m³

The density of gold is 19.3 metric tons meter meter cubed.
6 0
3 years ago
A man walks 400 m in the direction 45° north of east. Represent this vector graphically by
Marrrta [24]

Answer:

Explanation:

Coordinate system is one that describe the location of an object in a given plane. It implies the use of axes (coordinates) and points.

Given that the man in the question walks 400 m due north of east. The cardinal points can be used in this case, with the north and east cardinals as the required axis.

scale = \frac{length on drawing}{original length}

         = \frac{10}{400}

         = \frac{1}{40}

scale = 1:40

This is a reduced scale which implies that 1 cm on the drawing is equal to 40 m on the original length.

The man's direction is 45^{o} north of east.

The graphical drawing of the vector is herewith attached to this answer.

5 0
3 years ago
The power ratings of several motors are listed in the table. A 2 column table with 3 rows. The first column is labeled motor wit
Lapatulllka [165]

The statement  " Brand-W motor does 7,640 N of your toughest work." can be truthfully use.

Advertisement Rules:

  • An advertiser can not compare its products using the other companies name.
  • An advertiser can not make the false statement in its advertisement.

Here, the brand-W has the power rating of  7,640 W that is less than brand-Y. Advertiser cannot compare his brand using the name of Brand X, Y, or Z.

Therefore, the statement  " Brand-W motor does 7,640 N of your toughest work." can be truthfully use.

To know more about Advertisement Rules:

brainly.com/question/13679377

7 0
3 years ago
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