Question

A person walks into a room that has, on opposite walls, two plane mirrors producing multiple images. Find the distances from the person to the first three images seen in the left-hand mirror, when the person is 6.60 ft from the mirror on the left wall and 14.1 ft from the mirror on the right wall.

Answer 1

Answer:13.2,41.4,82.8 ft

Explanation:

Given Person is 6.60 ft from the left hand side mirror

Since the focal length of plane mirror is infinity therefore image and object are equidistant from mirror

Distance of first image on  left mirror is

$d_1=6.6+6.6=13.2 ft$

i.e. image is 13.2 ft away from object

Second image

Now the right mirror forms the image of object at distance of 14.1 ft right from right mirror so its image is formed in left mirror at a distance of 34.8 from left mirror

so image distance from person is

$d_2=34.8+6.6=41.4 ft$

Third image now form image of second image is formed on right mirror at a distance of 55.5 right from right mirror

and its mirror image is formed on left mirror at a distance of  76.2 left

from left mirror

$d_3=76.2+6.6=82.8 ft$