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3 years ago

PLEASE HELP!!! A) B) C) D)

Mathematics

1 answer:

Vlad1618 [11]3 years ago

4 0

Answer:

b i think

Step-by-step explanation:

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Unit 8 test study guide right triangles and trigonometry

tatiyna

Answer:

Hopefully, you can see the attachment. It's all on there but the "if" portion

7 0

3 years ago

Roberta wants to create 17 ounces of new hand lotion, with a minimum 15% concentration of beeswax, from a mixture of two lotions

Zarrin [17]

Answer:

Step-by-step explanation:

Given the inequality

0.21x + 0.05(17 - x) > 2.55 where x is the amount of 21% lotion needed

Given

0.21x + 0.05(17 - x) > 2.55

Open the parenthesis

0.21x + 0.85-0.05x > 2.55

Collect like terms

0.21x-0.05x+0.85>2.55

0.16x+0.85>2.55

0.16x>2.55-0.85

0.16x > 1.7

x > 1.7/0.16

x > 10.625

Hence she will need 21% lotion approximately greater than 10 ounces

6 0

3 years ago

Enlist any five common social rules all kinds of society

Delvig [45]

Answer:Shake hands when you meet someone.Make direct eye contact with the person you are speaking with.Unless the movie theater is crowded, do not sit right next to someone.Do not stand close enough to a stranger to touch arms or hips.Cover your coughs.

Step-by-step explanation:trust me

8 0

2 years ago

The coordinates of quadrilateral PQRS are P(–3, 0), Q(0, 4), R(4, 1), and S(1, –3). What best describes the quadrilateral?

denis-greek [22]

Answer:

Square

Step-by-step explanation:

Plot the vertices of the quadrilateral PQRS on the coordinate plane (see attached diagram). The diagram shows that this is a square. Let's prove it.

1. Find all sides lengths:

$PQ=\sqrt{(-3-0)^2+(0-4)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5\\ \\QR=\sqrt{(0-4)^2+(4-1)^2}=\sqrt{(-4)^2+(3)^2}=\sqrt{16+9}=\sqrt{25}=5\\ \\RS=\sqrt{(4-1)^2+(1-(-3))^2}=\sqrt{(3)^2+(4)^2}=\sqrt{9+16}=\sqrt{25}=5\\ \\SP=\sqrt{(1-(-3))^2+(-3-0)^2}=\sqrt{(4)^2+(-3)^2}=\sqrt{16+9}=\sqrt{25}=5$

All sides have the same lengths.

2. Find the slopes of all lines:

$PQ:\ \dfrac{4-0}{0-(-3)}=\dfrac{4}{3}\\ \\QR:\ \dfrac{1-4}{4-0}=-\dfrac{3}{4}\\ \\RS:\ \dfrac{-3-1}{1-4}=\dfrac{4}{3}\\ \\SP:\ \dfrac{0-(-3)}{-3-1}=-\dfrac{3}{4}$