Remark
You know the most about the trip on the way back and the total of the two trips.
Way Back
r = 30 mph
d = distance traveled
t = t - 1 where t = the time to go there which we know nothing about
Total Distance
2d = 25 mph * (t + t - 1)
2d = 25 * (2t - 1)
2d = 50t - 25 Divide by 2
2d = 50t/2 - 25/2
d = 25t - 12.5
Equation coming back
d = 30*(t - 1)
d = 30t - 30
Comment
Since the distances are the same, equate them.
Solution
25t - 12.5 = 30t - 30 Subtract 25t from both sides
25t - 25t -12.5 = 30t - 25t - 30 Combine like terms
-12.5 = 5t - 30 Add 30 to both sides
-12.5 + 30 = 5t - 30 + 30 Combine
17.5 = 5t Divide by 5
17.5/5 = t Divide and Switch
t = 3.5
t is the time going there
t - 1 is the time coming back
Total time = 2*t - 1 = 2*3.5 - 1 = 6
The total time is 6 hours. Answer
Answer:
2/3(3/4x-3/2) = 1/2x-1
(2x+1) - (x+3/2) = x - 1/2
Step-by-step explanation:
1) Distribute 2/3 to both 3/4x and -3/2
2/3(3/4x) = 6/12x which can be simplified as 1/2x
2/3(-3/2) = -6/6 which simplifies to -1
2/3(3/4x-3/2) = 1/2x-1
2) (2x+1) - (x+3/2) combine like terms
2x-x = x
1 - 3/2= 1- 1 1/2 ( change 3/2 into an improper fraction. 2 goes into 3 one time with one left over. Place the “leftover” back on top of the original denominator of 2)
1- 1 1/2 = -1/2, so
(2x+1) - (x+3/2) = x - 1/2
Answer: 22
Step-by-step explanation:
The area of the picture =l×b = 20×16=320
The length of the frame is 16
If the width is x ( and it's uniform)
672- 320= 352
Area of the frame = 16× x=352
x=352/16
x = 22
Answer:
"The area of EFGH is always One-half of the area of the rectangle."
Step-by-step explanation:
<em>Graph is attached.</em>
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The kite consists of 2 triangle, EFG and EHG.
The area of EFG:
where h is the height from F to EG
The area of EHG:
where 
is the height from H to EG
We also know that h + h _1 is the width of the rectangle and EG is the length of the rectangle
Thus,
Area of Kite = 
Also, Area of rectangle is rectangle length * rectangle width.
Thus, area of kite is always half of that of rectangle, the third choice is right.
