Answer:
For the function V(t)=24300(1.37)t, the rate of increase is 37%.
Step-by-step explanation:
The function represents the value (V) of the car over time (t). This type of function is exponential growth, which means for each year, the value of the vintage car will increase by a rate of 37%. Exponential growth functions are represented by the equation f(x)=ab^x, where 'a'=initial value, 'b'=the rate and 'x' represents time. In this case, our initial value of the car is $24,300 and the rate is 1.37. A rate of 1.37 indicates that the car will retain its initial value (1) as well as increase be an additional 37 percent (.37) over time.
Let x = amount of mortgage (aka the amount by the bank)
25% of the monthly income of $3000 is 0.25*3000 = 750 dollars
So using this rule, the family can pay up to $750 per month on mortgage
1% of the amount loaned (x) is equal to this figure, so
0.01*x = 750
0.01*x/0.01 = 750/0.01
x = 75000
Therefore, the most expensive mortgage this family can afford is $75,000. Anything higher and they go over budget.
Answer:
Hello your question is incomplete below is the complete question
What is wrong with the equation? integral^2 _3 x^-3 dx = x^-2/-2]^2 _3 = -5/72 f(x) = x^-3 is continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous at x = -3, so FTC2 cannot be applied The lower limit is less than 0, so FTC2 cannot be applied. There is nothing wrong with the equation. If f(2) = 14, f' is continuous, and f'(x) dx = 15, what is the value of f(7)? F(7) =
answer : The value of f(7) = 29
Step-by-step explanation:
Attached below is the detailed solution
Hence : F(7) - 14 = 15
F(7) = 15 + 14 = 29
The area is(s^2)/2-(900/5)/2=90
Answer:
false
Step-by-step explanation:
