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iren [92.7K]
3 years ago
11

8x – 2(x + 1) = 2(3x – 1)

Mathematics
1 answer:
Nina [5.8K]3 years ago
8 0
8x - 2(x + 1) = 2(3x - 1)

First, expand to remove parenthesis. / Your problem should look like: 8x - 2x - 2 = 6x - 2
Second, subtract 8x - 2x - 2 to get 6x - 2. / Your problem should look like: 6x - 2 = 6x - 2
Third, both sides are equal, so there are infinite solutions. The equation is always true.

Answer: infinite solutions

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Convert to slope form: 3x-4y=8 then graph the line on the grid.​
alexandr402 [8]

Answer: 3/4

Step-by-step explanation:

Graph the line using the slope and y-intercept, or two points.

Slope: 3/4

HOPE THIS HELPS :)

6 0
3 years ago
phyllis invested 66000 dollars, a portion earning simple interest rate of 5% per year and the rest earning a rate of 7% per year
Lelechka [254]

<u>Answer: </u>

Physliis invested 32000 dollar at 5% interest rate and 34000 dollar at 7% interest rate.

<u>Solution:</u>

Let Phyllis invest ‘x’ dollar at 5% per year and (66000-x) dollar at 7% per year.

We know,

\text { Simple interest }=\frac{\text {Principal} \times r a t e \times T i m e}{100}

In the question it is given that Simple interest earned from both the investments at the end of the year is $3980.

Using the given below equation, we will try to find out the investments at each rate.

\begin{array}{l}{\frac{x \times 5 \times 1}{100}+\frac{(66000-x) \times 7 \times 1}{100}=3980} \\\\ {\frac{5 x}{100}+\frac{462000-7 x}{100}=3980} \\\\ {\frac{5 x+462000-7 x}{100}=3980} \\\\ {-2 \mathrm{x}+462000=3980 \times 100} \\\\ {-2 \mathrm{x}=398000-462000} \\\\ {-2 \mathrm{x}=-64000} \\\\ {\mathrm{x}=\frac{-64000}{-2}}\end{array}

x = 32000

We can calculate amount for 7% interest rate by,

(66000-32000) =34000

Thus Phyllis invested 32000 dollar at 5% interest rate and 34000 dollar at 7% interest rate.

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
Write a linear equation representing the information shown in the table.
Law Incorporation [45]

Answer:

A

Step-by-step explanation:

This is how I write

y=kx+m

but I have seen some write it like this:

y=mx+b

Well both of them are the same thing, I'll use the first one because I'm more comfortable with it.

y=kx+m

To find out what k

k =  \frac{y2 - y1}{x2 - x1}

So you first need to choose two points.

I'll go for (0,-5) and (2,0)

k =  \frac{0 - 5}{2 - 0}

k = \frac{ - 5}{2}

Now you could insert k into the equation and it will look like this.

y =  \frac{ - 5}{2}x + m

To find out what m is just pick one point and insert it into the equation. So if I pick (0,-5). 0=X therefore it should be replaced by x and -5=y therefore it should also be replaced by y.

- 5 =  \frac{ - 5}{2} \times 0 + m

m=-5

Try it with another point to see if you get the same answer. this time I'll pick (-6,10)

10=  \frac{ - 5}{2} \times( - 6)+ m

m= -5

The equation will be y=-5/2x-5)

8 0
3 years ago
What is an equation of the line that passes through the points (3, 4) and (-4, -3)?
Rudik [331]

Answer:

(7,7)

Step-by-step explanation:

7 0
3 years ago
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