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mixas84 [53]
3 years ago
9

Identify the type I error and the type II error that corresponds to the given hypothesis. The proportion of people who write wit

h their left hand is equal to 0.22.
Which of the following is a type I​ error?
A. Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually different from 0.29
B. Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually different from 0.29
C. Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29
D. Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29
Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
4 0

Answer:

Type I error is to Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29.

Type II error is Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is different from 0.29.

Step-by-step explanation:

We are given the following hypothesis below;

Let p = <u><em>proportion of people who write with their left hand</em></u>

So, Null Hypothesis, H_0 : p = 0.22     {means that the proportion of people who write with their left hand is equal to 0.22}

Alternate Hypothesis, H_A : p \neq 0.22      {means that the proportion of people who write with their left hand is different from 0.22}

Now, Type I error states that we conclude that the null hypothesis is rejected when in fact the null hypothesis was actually true. Or in other words, it is the probability of rejecting a true hypothesis.

So, in our question; Type I error is to Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29.

Type II error states that we conclude that the null hypothesis is accepted when in fact the null hypothesis was actually false. Or in other words, it is the probability of accepting a false hypothesis.

So, in our question; Type II error is Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is different from 0.29.

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F(x)=-3x-2 find f(3)
TiliK225 [7]

Answer:

f(3) = -11

Step-by-step explanation:

f(x) = -3x-2

let x=3 and replace it in the above equation

f(3) = -3(3) -2

f(3) = -9 -2

f(3) = -11


4 0
4 years ago
three terms of an arithmetic sequence are shown below. Which recursive formula defines the sequence? f(1) = 6, f(4) = 12, f(7) =
Viefleur [7K]
A = 6
tn = a + (n - 1)d
t4 = 6 + 3d = 12
3d = 12 - 6 = 6
d = 6/3 = 2
f(n + 1) = f(n) + 2
4 0
3 years ago
Read 2 more answers
PLZ CHECK MY ANSWER. Round your answer to the nearest tenth.
Umnica [9.8K]

Answer:

D. 70.34 cm^2

Step-by-step explanation:

Area of sector of a circle is given as θ/360*πr²

Where,

r = radius = 12 cm

θ = 56°

Use 3.14 as π

Plug in the values into the formula and solve

area = \frac{56}{360}*3.14*12^2

area = 70.34

Area of the sector ABC = 70.34 cm^2

The answer is D

4 0
4 years ago
What would the answer be ? Thank You!!
Bogdan [553]

Answer:

2.33 = BC

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp / adj

tan B = AC / BC

tan 25 = AC / 5

Multiply each side by 5

5 tan 25 = BC

2.331538291 = BC

To the nearest hundredth

2.33 = BC

3 0
3 years ago
Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o
kirza4 [7]

Answer:

a) H0: \sigma = 1.34

H1: \sigma \neq 1.34

b) df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

c) t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

\sigma_o =1.34 the value that we want to test

p_v represent the p value for the test

t represent the statistic  (chi square test)

\alpha=0.01 significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: \sigma = 1.34

H1: \sigma \neq 1.34

The statistic is given by:

t=(n-1) [\frac{s}{\sigma_o}]^2

Part b

The degrees of freedom are given by:

df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

Part c

Replacing the info we got:

t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0
3 years ago
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